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How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
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How will you prepare 500ml of 1N KOH solution?
To prepare 500mL of 1N KOH solution, you will need to dissolve 20 grams of KOH (potassium hydroxide) in enough water to make a final volume of 500mL. The molarity of the solution will be 1N, meaning it will contain 1 mole of KOH per liter of solution. Remember to wear appropriate safety gear such as gloves and goggles when working with chemicals.
You are provided with a 1000ppm sodium solution describe how you would prepare a volume of 200ml with a concentration of 5ppm sodium in a two step dilution?
To prepare a 200ml solution with a sodium concentration of 5ppm from a 1000ppm stock solution, you will first dilute the stock solution by a factor of 200. So, take 0.2ml of the 1000ppm solution and dilute it to 40ml with water. This will give you a solution with a concentration of 50ppm. Then, take 0.4ml of this 50ppm solution and dilute it to a final volume of 200ml with water to achieve the desired 5ppm sodium concentration.
How much ethanoic acid is needed to make 500ml of 0.1M solution?
To make a 0.1M solution of ethanoic acid in 500ml, you need 25g of ethanoic acid (CH3COOH) which is equivalent to approximately 0.416 moles.
How many grams of naoh are needed to prepare 500ml of 125M naoh?
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
How would you prepare 500 mL of a 1M solution of acetic acid -HC2H3O2- from a stock solution of 6M of acetic acid?
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.
How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
Prepare 500ml of 0.12N HCL solution?
To prepare 500ml of 0.12N HCl solution, you will need to dilute a concentrated hydrochloric acid solution. To do this, measure out 2.5ml of concentrated HCl (37% w/w) and dilute it to 500ml with distilled water. Be sure to wear appropriate safety equipment and handle the acid with caution.
How will you prepare 500ml of 1N KOH solution?
To prepare 500mL of 1N KOH solution, you will need to dissolve 20 grams of KOH (potassium hydroxide) in enough water to make a final volume of 500mL. The molarity of the solution will be 1N, meaning it will contain 1 mole of KOH per liter of solution. Remember to wear appropriate safety gear such as gloves and goggles when working with chemicals.
You are provided with a 1000ppm sodium solution describe how you would prepare a volume of 200ml with a concentration of 5ppm sodium in a two step dilution?
To prepare a 200ml solution with a sodium concentration of 5ppm from a 1000ppm stock solution, you will first dilute the stock solution by a factor of 200. So, take 0.2ml of the 1000ppm solution and dilute it to 40ml with water. This will give you a solution with a concentration of 50ppm. Then, take 0.4ml of this 50ppm solution and dilute it to a final volume of 200ml with water to achieve the desired 5ppm sodium concentration.
How much ethanoic acid is needed to make 500ml of 0.1M solution?
To make a 0.1M solution of ethanoic acid in 500ml, you need 25g of ethanoic acid (CH3COOH) which is equivalent to approximately 0.416 moles.
Hom much of 50mg per ml solution should be added to a 500ml solution to get 50 micrograms per milliliter?
To achieve a concentration of 50 micrograms per milliliter, you would add 1 milliliter of the 50mg per ml solution to the 500ml solution. This would result in a total volume of 501ml with a concentration of 50 micrograms per milliliter.
How do you prepare 0.5naoh direct pellets?
10gm in 500ml
How much 100x TAE buffer will it take to make 500ml of 1x TAE solution?
to make 500ml of 1x TAE solution we have to take 5ml of 100x TAE solution. mix it in 495 ml of deionized water.
How many grams of naoh are needed to prepare 500ml of 125M naoh?
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
The mass of solute in a given volume of solution or mass volume?
Yes, this is exactly it. If you don't have a litre, it is still a certain molarity solution, provided you know the amount of moles. For example. 2 moles in 500ml. If there are 2 moles in every 500ml, there will be 4 moles in every 1000ml, i.e. 4 molar.
How do you prepare a 500mL of 1M of NaCl solutuion?
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
What weight of solid CoCl2 would be need to prepare 500ML of 0.150M CoCl2 solution?
To calculate the weight of solid CoCl2 needed, you can use the formula: weight = (molarity) x (volume) x (molar mass) Substitute the values: weight = 0.150 mol/L x 0.5 L x 129.84 g/mol = 9.74 g of CoCl2 is needed.
