molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
Molarity = moles of solute/volume of solution
2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters
= 0.132 Molarity of NaOH
8g
You weight 14,5 gramm KOH in a bottle and than fill that bottle with deionized water till it holds 500ml.
The concentration of this solution (in NaOH) is 40 g/L.
The answer is 3grams dude!
Cr(NO3)3-238g/mol Moles in 500ml, 2.08x500/1000=1.04mol. Mass of Cr(NO3)3=1.04x238=247.52g
you can only use the following glassware 5 10 20 25 and 50ml pipette 50 100 200 or 500ml volumetric flasks
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
You weight 14,5 gramm KOH in a bottle and than fill that bottle with deionized water till it holds 500ml.
The concentration of this solution (in NaOH) is 40 g/L.
The answer is 3grams dude!
add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)
Mol.Wt =248.17Molarity =( Wt/ Mol.Wt ) /No:of litres of solution0.1 =( Wt / 248.17) / 0.5Wt =0.1 *0.5*248.17Wt = 12.4085g in 500ml of solution.
Cr(NO3)3-238g/mol Moles in 500ml, 2.08x500/1000=1.04mol. Mass of Cr(NO3)3=1.04x238=247.52g
you can only use the following glassware 5 10 20 25 and 50ml pipette 50 100 200 or 500ml volumetric flasks
10gm in 500ml
C1V1 = C2V2 (500ml)(1M) = (Xml)(6M) ( divide both sides by 6 in this case ) = 83.3ml Put this 83.3ml of 6M acid into a 600ml beaker and add 416.7ml to get 500ml total.
Yes, this is exactly it. If you don't have a litre, it is still a certain molarity solution, provided you know the amount of moles. For example. 2 moles in 500ml. If there are 2 moles in every 500ml, there will be 4 moles in every 1000ml, i.e. 4 molar.
to make 500ml of 1x TAE solution we have to take 5ml of 100x TAE solution. mix it in 495 ml of deionized water.