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If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl.
However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g.
So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL.
You now have 100mL of a 5M NaCl solution.
What else can I help you with?
Can you autoclave 1M HCl solution?
It is not recommended to autoclave a 1M HCl solution as autoclaving acids can lead to the generation of corrosive fumes and potential damage to the autoclave equipment. It is safer to prepare fresh 1M HCl solution as needed using appropriate lab practices.
How many grams of magnesium hydroxide required to make 1M of the solution?
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
How do you prepare 1M ethanol?
You take 1 mol = 46 gram of pure alcohol (or equivalent 46 * [100 / masspercentage] of diluted) and add it up with water while stirring to make it 1 Litre.[Roughly you'd have to take 60 mL 96% ethanol (this is commercially available, don't use denaturated spirit!) and fill up to 1 L.]
How do you prepare a solution containing 300ml of 1M Sodium Sulfate?
That is a poorly worded question. The way you have worded it could be answered correctly by instructing you to "Pour 300ml of 1M solution in a swimming pool."The question is usually posed in the form of "How much sodium sulfate is needed to produce 300 ml of 1M solution?" Presuming you intend the latter, you would prepare 300 ml of 1M solution by mixing 300/1000 of a mole of sodium sulfate with sufficient water to produce 300 ml of solution.Note the difference between Molar and Molal: 1M = 1 mole per liter of solution, 1 molal = 1 mole per liter of water. This distinction has a major effect on the wording of your answer.300 ml / 1000 ml = 3/10 = 0.3000One mole of sodium sulfate (Na2SO4) has the formula weight of 142.04314 g/mol as shown below:fw Na x 2 = 22.98977 g/mol x 2 = 45.97954 g/molfw S = 32.066 g/molfw O x 4 = 15.994 g/mol x 4 = 63.9976 g/mol45.97954 g/mol + 32.066 g/mol + 63.9976 g/mol = 142.04314 g/molThe mass of 0.3000 mol x 142.04314 g/mol = 42.613 g.Note: The final answer was rounded to the thousandths place because the formula weight for Sulfur was the least precise term.
How much is 1 cube or soil?
The price of soil can vary depending on the quality, brand, and location. On average, a cubic yard of topsoil can range from $20 to $100, but prices may differ based on these factors. The price for a single cubic foot of soil might typically range from $1 to $5.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
If you have 2 liters of 2 M NaCl you take 500 ml of that and add it to 500ml of pure water the new 1000 ml preparation is now?
A solution of NaCl 1 M.
How do you CONVERT 0.1m NaCl to 1m NaCl?
Increase the concentration of NaCl evaporating the water.
How many grams of NaCl are required to completely neutrilaze 100ml of 1M of H2SO4?
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
How would you prepare 500 mL of a 1M solution of acetic acid -HC2H3O2- from a stock solution of 6M of acetic acid?
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.
How many grams of NaCl are required to completely neutralize 100ml of 1M of H2SO4?
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
When mixing 1m of a strong acid and a strong base you get?
Let's see. NaOH + HCl = NaCl + H2O The usual salt ( NaCl ) and water.
How do you prepare 1M from 10mM Tris-HCL?
To prepare 1M Tris-HCl from a 10mM solution, you would need to dilute the 10mM solution by a factor of 100. This means you would mix 1 part of the 10mM solution with 99 parts of water to achieve a final concentration of 1M Tris-HCl.
Will mixing equal quantities of 1m solutions of the following give an acidic basic or neutral solution?
Mixing equal quantities of 1M HCl and 1M NaOH solutions will give a neutral solution because they will react to form water and a salt (NaCl).
How do you prepare 0.02m Naoh from 1M Naoh solution?
To prepare 0.02M NaOH from 1M NaOH solution, you will need to dilute the 1M solution. Use the formula: C1V1 = C2V2, where C1 is the concentration of the stock solution (1M), V1 is the volume of the stock solution you will use, C2 is the desired concentration (0.02M), and V2 is the final volume of the diluted solution. Calculate the volume of 1M NaOH solution (V1) needed to make the desired 0.02M concentration and dilute it with water to reach the desired volume (V2).
How can you prepare 1M H2SO4?
To prepare 1M H2SO4 solution, you would need to dilute concentrated sulfuric acid (approximately 18M) by adding the appropriate amount of water. To make 1L of 1M H2SO4 solution, you would mix approximately 55.5 mL of concentrated sulfuric acid with about 944.5 mL of water in a volumetric flask while taking proper safety precautions.
How to prepare 1m hcl from 35 percent hcl?
To prepare 1M HCl solution from 35% HCl solution, you would need to dilute the 35% HCl with water. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration (1M), and V2 is the final volume (1 liter in this case). Calculate the volume of 35% HCl needed to achieve a 1M solution, then add water to make up the total volume to 1 liter.
