Increase the concentration of NaCl evaporating the water.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Your answer is 2. 1m = 100cm 1cm = .01m
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
6.9 m = 6.9m * 1m/1m = 6.9m * 100cm/1m = 6.9 * 100cm = 690 cm
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
Let's see. NaOH + HCl = NaCl + H2O The usual salt ( NaCl ) and water.
1mEq NaCl = 58,4 mg NaCl
100cm = 1m 1cm = 1m/100 472cm/100cm/m = 4.72m
100cm = 1m 1 meter
1m = 100cm13 * 100 = 1300cm
1m = 100cm 890m = 89000cm
just multiply it with 1m.