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That is a poorly worded question. The way you have worded it could be answered correctly by instructing you to "Pour 300ml of 1M solution in a swimming pool."

The question is usually posed in the form of "How much sodium sulfate is needed to produce 300 ml of 1M solution?" Presuming you intend the latter, you would prepare 300 ml of 1M solution by mixing 300/1000 of a mole of sodium sulfate with sufficient water to produce 300 ml of solution.

Note the difference between Molar and Molal: 1M = 1 mole per liter of solution, 1 molal = 1 mole per liter of water. This distinction has a major effect on the wording of your answer.

  • 300 ml / 1000 ml = 3/10 = 0.3000
  • One mole of sodium sulfate (Na2SO4) has the formula weight of 142.04314 g/mol as shown below:

fw Na x 2 = 22.98977 g/mol x 2 = 45.97954 g/mol

fw S = 32.066 g/mol

fw O x 4 = 15.994 g/mol x 4 = 63.9976 g/mol

45.97954 g/mol + 32.066 g/mol + 63.9976 g/mol = 142.04314 g/mol

The mass of 0.3000 mol x 142.04314 g/mol = 42.613 g.

Note: The final answer was rounded to the thousandths place because the formula weight for Sulfur was the least precise term.

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