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How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
Wiki User
∙ 10y ago
500ml = 500cm3 = 0.5dm3
0.250M = 0.250mol/dm3
number of moles = molarity x volume
number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol
0.125mol of NaCl is needed to prepare the required solution.
Wiki User
∙ 10y ago
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