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How many NaOH required to neutralize complitly4.9 gms of H2SO4?
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
For every mole of sodium hydroxide, you need 1 mole of sulfuric acid for neutralization. The molar mass of sodium hydroxide (NaOH) is 40.0 g/mol and sulfuric acid (H2SO4) is 98.1 g/mol. So, to neutralize 40 g of NaOH (1 mole), you would need 98.1 g of H2SO4 (1 mole). Therefore, to neutralize 10.0 g of NaOH, you would need 24.53 g of H2SO4.
What volume of 0.744 Molarity of NaOH is required to titrate 10.00ml of 0.526 M H2SO4?
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
What is the number of moles of NaOH required to neutralize 1 mole of H2SO4?
Well, darling, if we're talking about a 1:2 molar ratio between NaOH and H2SO4, then you'd need 2 moles of NaOH to neutralize 1 mole of H2SO4. It's all about those stoichiometry dance moves, honey. Just make sure you're not tripping over your chemical equations!
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many NaOH required to neutralize complitly4.9 gms of H2SO4?
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
For every mole of sodium hydroxide, you need 1 mole of sulfuric acid for neutralization. The molar mass of sodium hydroxide (NaOH) is 40.0 g/mol and sulfuric acid (H2SO4) is 98.1 g/mol. So, to neutralize 40 g of NaOH (1 mole), you would need 98.1 g of H2SO4 (1 mole). Therefore, to neutralize 10.0 g of NaOH, you would need 24.53 g of H2SO4.
What volume of 0.744 Molarity of NaOH is required to titrate 10.00ml of 0.526 M H2SO4?
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
What is the number of moles of NaOH required to neutralize 1 mole of H2SO4?
Well, darling, if we're talking about a 1:2 molar ratio between NaOH and H2SO4, then you'd need 2 moles of NaOH to neutralize 1 mole of H2SO4. It's all about those stoichiometry dance moves, honey. Just make sure you're not tripping over your chemical equations!
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many grams of NaOH and H2SO4 are needed to produce 200 g Na2SO4?
To produce 200 g of Na2SO4, you would need 80 g of NaOH (sodium hydroxide) and 98 g of H2SO4 (sulfuric acid) based on their respective molar masses and stoichiometry in the balanced chemical equation for the reaction.
A 25.00ml sample of h2so4 requires 22.65 ml of the 0.550m naoh for its titration what was the concentration of sulfuric acid?
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
How many moles of NaOH react with 1 mole of H2SO4?
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
How many grams of NaOH would you need to make 4 litters of 8 M NaOH?
To calculate the grams of NaOH needed, use the formula: grams = molarity x volume x molar mass. First, convert the volume to liters (4 liters). Next, calculate the grams using 8 M as the molarity and the molar mass of NaOH. This will give you the amount of NaOH required to make 4 liters of 8 M NaOH solution.
How much 66 baume sulfuric acid is required to neutralize 350lbs of sodium hydroxide?
66 Baume Sulfuric Acid is contains 93.2% H2SO4 by weight in water. It requires 1 lbmol of H2SO4 to neutralize 2 lbmol of NaOH. Assuming that 350 lbs of NaOH is pure, there are 8.75 lbmol of NaOH. (Divide 350lb by 40 lb/lbmol, the MW of NaOH.) It takes 4.375 lbmol of H2SO4 to neutralize the 350 lb of NaOH because there are 2 lbmol of H per lbmol of H2SO4 and one lbmol of OH per lbmol of NaOH. 4.375 lbmol is equivalent to 428.75 lb of H2SO4. (Multiply by 98 lb/lbmol, the MW of H2SO4.) Then divide by 93.2% or 0.932 to get the quanty of 66 Baume containing 428.75 lb of H2SO4. 460 lb of 66 Baume. The density of 66 Baume is 1.8354 g/cm3 which is equivalent to 15.32 lb/gallon. (Mulitply by 8.345.) Finally, it requires 30 gallons of 66 baume to neutralize 350 lbs of NaOH. (Divide 460 by 15.32.)
Which salt is produced when H2SO4 reacts with NaOH?
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
What mass of NaOH is required to make up 100 mL of a 0.5000 M solution?
Two parts.Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters )0.5000 M NaOH = X moles/0.1 L= 0.05 moles NaOH--------------------------------now,0.05 moles NaOH (39.998 grams/1 mole NaOH)= 1.99 grams NaOH required====================( could call it 2.00 grams )
