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How many atoms are present in 16g of O and 8g of S?
To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.
How many types of atoms are present in Na2SO4?
Na2SO4Three different types of atoms.2 atoms of sodium.1 atom of sulfur.4 atoms of oxygen.This compound is called,sodium sulfate.
How many atoms in molecules of Na2 So4?
Two sodium (Na) atoms One sulphur (S) atom Four oxygen (O) atoms So totally 7 atoms are present in a molecule of sodium sulphate.
What is the number of S atoms in 0.660 mole of S?
There are 0.660 moles of sulfur atoms in 0.660 moles of S. To find the number of atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23), so there are 3.97 x 10^23 sulfur atoms present.
How many total atoms in 3 Na2 s O4?
Multiply the coefficient times the subscript for each element. For 3Na2SO4, there are a total of 6 sodium atoms, 3 sulfur atoms, and 12 oxygen atoms.
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
How many S atoms are present in 7.00 mg of allicin?
7,00 mg of allicin contain 0,519.10e20 sulfur atoms.
How many atoms of s and o were present in the reaction 2so2 plus o2--2so3?
In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.
How many atoms are present in 16g of O and 8g of S?
To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms. For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms. Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.
How many types of atoms are present in Na2SO4?
Na2SO4Three different types of atoms.2 atoms of sodium.1 atom of sulfur.4 atoms of oxygen.This compound is called,sodium sulfate.
How many atoms in molecules of Na2 So4?
Two sodium (Na) atoms One sulphur (S) atom Four oxygen (O) atoms So totally 7 atoms are present in a molecule of sodium sulphate.
What is the number of S atoms in 0.660 mole of S?
There are 0.660 moles of sulfur atoms in 0.660 moles of S. To find the number of atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23), so there are 3.97 x 10^23 sulfur atoms present.
How many total atoms in 3 Na2 s O4?
Multiply the coefficient times the subscript for each element. For 3Na2SO4, there are a total of 6 sodium atoms, 3 sulfur atoms, and 12 oxygen atoms.
How many atoms each in formula 2Na2SO4?
There are a total of 16 atoms in the formula 2Na2SO4. This includes 4 Na atoms, 2 S atoms, and 8 O atoms.
How many atoms are in Hg2sCl2?
There are five atoms in Hg2SCl2: 2 atoms of mercury (Hg), 1 atom of sulfur (S), and 2 atoms of chlorine (Cl).
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
How many atoms are in a molecule of SO4?
5 atoms 1 atom of S + 4 atoms of O S's index is 1 so only 1 atom (no index is 1) + O's index is 4 so 4 atoms
