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How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many moles of each atom are in 2.00moles of sulfur trioxide?
How_many_moles_of_each_atom_are_in_2.00moles_of_sulphur_trioxide
6.11 mole of sulfur trioxide have a mass of how many grams?
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
How many moles of sulfur trioxide are formed from 3 moles of sulfur dioxide?
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The compound whose formula is SO3 is called?
The compound with the formula SO3 is called sulfur trioxide.
How many moles of sulfur trioxide will be produced when two moles of sulfur combine with three moles of oxygen?
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many moles of each atom are in 2.00moles of sulfur trioxide?
How_many_moles_of_each_atom_are_in_2.00moles_of_sulphur_trioxide
6.11 mole of sulfur trioxide have a mass of how many grams?
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
Number of different elements in sulfur trioxide?
There are two elements present in sulfur trioxide, which are: Sulfur and Oxygen.The following formula represents sulfur trioxide: SO3As there is one atom of sulfur and three atoms of oxygen (trioxide).
What is the limiting reactant when 3.1 moles of SO2 react with 2.7 moles of O2 to produce sulfur trioxide?
The limiting reactant is oxygen.
How many moles of sulfur trioxide are formed from 3 moles of sulfur dioxide?
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The compound whose formula is SO3 is called?
The compound with the formula SO3 is called sulfur trioxide.
What is the name of the compound SO3?
Sulfur tetraoxide 2- SO4 is sulfate
What is the compound for sulfur trioxide?
Formula: SO3
What is sulfur trioxide's molecular geometry?
Sulfur trioxide has a trigonal planar molecule.
Is trioxide good or bad for us?
Sulfur trioxide is a byproduct of sulfuric acid. In large quantities, sulfur trioxide can be deadly. For the most part, small quantities of sulfur trioxide will not hurt you.
