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How many moles is 8.0g of ammonium nitrate?
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of the compound. The molar mass of ammonium nitrate (NH4NO3) is 80.04 g/mol. Therefore, 8.0g ÷ 80.04 g/mol = 0.1 moles of ammonium nitrate.
How many atoms are present in ammonium nitrate?
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How many mole is 8.0g of ammonium nitrate?
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of ammonium nitrate (NH4NO3). The molar mass of NH4NO3 is 80.05 g/mol. Therefore, 8.0g ÷ 80.05 g/mol = 0.1 moles of ammonium nitrate.
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many atoms are represented in the formula for ammonium nitrate?
9 atoms Here is the formula for ammonium nitrate. NH4NO3 This shows there are two nitrogen atoms, 4 hydrogen, and 3 oxygen. So 1 (nitrogen) + 1(nitrogen) + 4(hydrogen) + 3(oxygen) = 9 atoms
How many moles of nitrogen gas are produced when ammonium nitrate reacts?
1 mole of ammonium nitrate produces one mole of nitrogen. Actually the amount (in moles) of nitrogen will depend on how much NH4NO3 you are starting with, what other reactant you are combining it with and whether or not the NH4NO3 completely reacts. Since you will never be able to retrieve all of the nitrogen (either the NH4 or the NO3 will retain some nitrogen depending upon the reaction), you can reasonably expect to get 1 mole of N2 for each 14.01 grams of Ammonium nitrate that COMPLETELY reacts.
How many moles is 8.0g of ammonium nitrate?
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of the compound. The molar mass of ammonium nitrate (NH4NO3) is 80.04 g/mol. Therefore, 8.0g ÷ 80.04 g/mol = 0.1 moles of ammonium nitrate.
How many atoms are present in ammonium nitrate?
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How many different elemnts in ammonium nitrate?
The chemical formula for ammonium nitrate is NH4NO3. It consists of 3 elements: nitrogen, hydrogen and oxygen.
How many mole is 8.0g of ammonium nitrate?
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of ammonium nitrate (NH4NO3). The molar mass of NH4NO3 is 80.05 g/mol. Therefore, 8.0g ÷ 80.05 g/mol = 0.1 moles of ammonium nitrate.
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many different elements are present there in ammonium nitrate?
Ammonium nitrate contains three different elements: nitrogen (N), oxygen (O), and hydrogen (H).
How many elements are there in one molecule in ammonium nitrate?
There are 19 atoms in one molecule of ammonium nitrate: 2 nitrogen atoms, 4 oxygen atoms, and 9 hydrogen atoms.
How many moles of nitrogen are in 650 moles of ammonium carbonate How many grams of this compound supply this much nitrogen?
The formula unit for the usual form of solid ammonium carbonate is (NH4)2CO3.H2O. This formula shows that each formula unit contains two atoms of nitrogen. Because nitrogen forms diatomic molecules at standard temperature and pressure, the number of moles of nitrogen is therefore the same as the number of formula units of ammonium carbonate, stated to be 650. The gram formula unit mass of this solid ammonium carbonate is 114.10. Therefore, 114.10(650) or 7.42 X 103 grams of the solid, to the justified number of significant digits, will be required.
How many elememts in ammonium nitrate?
Ammonium nitrate(NH4NO3) composition:Nitrogen = 2 atomsOxygen = 3 atomsHydrogen = 4 atoms
How many atoms are represented in the formula for ammonium nitrate?
9 atoms Here is the formula for ammonium nitrate. NH4NO3 This shows there are two nitrogen atoms, 4 hydrogen, and 3 oxygen. So 1 (nitrogen) + 1(nitrogen) + 4(hydrogen) + 3(oxygen) = 9 atoms
How many moles of oxygen combine with 5 moles of Nitrogen?
Depends on what substance is being formed. If it's nitric oxide (NO), then 5. If it's nitrogen dioxide (NO2), then 10. If nitrate (NO3), then 15.
