Depends on what substance is being formed. If it's nitric oxide (NO), then 5. If it's nitrogen dioxide (NO2), then 10. If nitrate (NO3), then 15.
Zero
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
0.44g. Molecular weight is 24.3. 0.44/24.3 is 0.0181 moles
4.561 / 28 = 0.163 moles of nitrogen.
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
15 grams of nitrogen are equal to 1,071 moles.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
16 grams of oxygen how many moles is 0,5 moles.
To determine the number of moles of nitrogen and oxygen in a given volume like a cubic foot, you would first need to know the pressure and temperature of the gas. Then you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. So without knowing the pressure and temperature, it is not possible to determine the number of moles of nitrogen and oxygen in a cubic foot.
Absolutely none, as there is no oxygen in hydrogen cyanide. Its formula is HCN--one atom each of hydrogen, carbon and nitrogen.