0.0999458293608 moles
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of ammonium nitrate (NH4NO3). The molar mass of NH4NO3 is 80.05 g/mol. Therefore, 8.0g ÷ 80.05 g/mol = 0.1 moles of ammonium nitrate.
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
The molarity can be calculated by first converting grams of sodium hydroxide to moles, then dividing by the volume of the solution in liters. In this case, the molar mass of NaOH is 40 g/mol. So, 80g is 2 moles. With a volume of 0.5 L, the molarity is 2 moles / 0.500 L = 4 M.
first we work out the Mr. Mr= 80g Then we find out the Mr of Oxygen in NH4NO3. Mr of oxygen=48g Then we do 40/80 which equals 0.5 then we multiply it by 100 and we get 50% This is our Percentage by mass.
To find the amount of KCl that remains in solution at 20 degrees Celsius, you can use the principle of solubility. Calculate the maximum amount of KCl that can dissolve in 200g of water at 20 degrees Celsius using a solubility chart. Once you have this value, compare it to the initial 80g of KCl to determine how much remains in solution after cooling.
To find the number of moles in 8.0g of ammonium nitrate, you need to divide the given mass by the molar mass of ammonium nitrate (NH4NO3). The molar mass of NH4NO3 is 80.05 g/mol. Therefore, 8.0g ÷ 80.05 g/mol = 0.1 moles of ammonium nitrate.
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
To find the molarity, we first need to calculate the number of moles of NaOH. The molar mass of NaOH is 40 g/mol (sodium=23g/mol, oxygen=16g/mol, hydrogen=1g/mol). Thus, 80g NaOH is 2 moles (80g / 40g/mol). Given 1L of solution, the molarity is 2 moles / 1 L = 2 M.
The molarity can be calculated by first converting grams of sodium hydroxide to moles, then dividing by the volume of the solution in liters. In this case, the molar mass of NaOH is 40 g/mol. So, 80g is 2 moles. With a volume of 0.5 L, the molarity is 2 moles / 0.500 L = 4 M.
80g = 0.17637 pounds
0.008hg to 80g
An 80g ps3 can hold 80g's of space. To compare to a mp3, it can hold 81920 megabytes, and one song equals about 5 megabytes. So image how many songs it can hold. A lot!!!
An 80g Manadarin has roughly 36 cal
Well 80g is equivalent to 0.18 pounds and there are 14 pounds in a stone so that would make 80g approximately 0.01 stones.
An 80g Manadarin has roughly 36 cal
An 80g bag of Rainbow Drops typically contains around 6 ProPoints, as each 10g portion is approximately 1 ProPoint.
The Marlin model 80G was a promotional model that was made from 1960-1965.