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How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many g of nitrogen are in 35.8kg of ammonium nitrate?
To calculate the amount of nitrogen in ammonium nitrate, we first need to determine its molecular formula, which is NH4NO3. This means that there is one nitrogen atom in each molecule. One mole of NH4NO3 weighs approximately 80 grams, and contains one mole of nitrogen which weighs about 14 grams. To find the amount of nitrogen in 35.8 kg of ammonium nitrate, we can set up a simple proportion: (35.8 kg / 80 kg) * 14 g = 6.29 g of nitrogen.
How many atoms of nitrogen are in 10g of NH4NO3?
One mole of NH4 (ammonium) has one mole of nitrogen atoms and four moles of hydrogen atoms, for a total of five moles of atoms. Multiply by Avogadro's Number to convert moles of atoms to atoms.
What is the mass percent of nitrogen in ammonium carbonate?
The molecular formula of ammonium carbonate is (NH4)2CO3. The molar mass of nitrogen in ammonium carbonate is 28.02 g/mol. The molar mass of ammonium carbonate is 96.09 g/mol. To calculate the mass percent of nitrogen in ammonium carbonate, you would divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100. This gives a mass percent of nitrogen in ammonium carbonate of around 29.1%.
What is the percent by mass of oxygen in NO2?
first we work out the Mr. Mr= 80g Then we find out the Mr of Oxygen in NH4NO3. Mr of oxygen=48g Then we do 40/80 which equals 0.5 then we multiply it by 100 and we get 50% This is our Percentage by mass.
What is the percent nitrogen in NH4NO3?
The percent nitrogen in NH4NO3 is 35.04%. This can be calculated by dividing the molar mass of nitrogen in the compound by the molar mass of the entire compound and then multiplying by 100.
How many atoms of nitrogen are in 20g of NH4NO3?
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
What compound has a lower percent of mass by nitrogen- NO or N2O3?
The oxide N2O3 has a lower percent of mass nitrogen.
What is the percent of nitrogen in CN2H4O?
The molar mass of CN2H4O is 42 g/mol. The molar mass of nitrogen is 14 g/mol. To find the percent of nitrogen in CN2H4O, divide the molar mass of nitrogen by the molar mass of CN2H4O and multiply by 100. The percent of nitrogen in CN2H4O is approximately 33.3%.
What is the mass percent of nitrogen in NF3?
To find the mass percent of nitrogen in NF3, you need to calculate the molar mass of NF3 and then determine the mass of nitrogen in one mole of NF3. The molar mass of NF3 is 71.001 g/mol. The molar mass of nitrogen in NF3 is 14.007 g/mol. Therefore, the mass percent of nitrogen in NF3 is (14.007 g/mol / 71.001 g/mol) * 100% ≈ 19.76%.
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many g of nitrogen are in 35.8kg of ammonium nitrate?
To calculate the amount of nitrogen in ammonium nitrate, we first need to determine its molecular formula, which is NH4NO3. This means that there is one nitrogen atom in each molecule. One mole of NH4NO3 weighs approximately 80 grams, and contains one mole of nitrogen which weighs about 14 grams. To find the amount of nitrogen in 35.8 kg of ammonium nitrate, we can set up a simple proportion: (35.8 kg / 80 kg) * 14 g = 6.29 g of nitrogen.
What is the formula mass and chemical formula for ammonium nitrate?
The chemical formula of ammonium nitrate is NH4NO3.The molecular mass is 80,052 g.
How many atoms of nitrogen are in 10g of NH4NO3?
One mole of NH4 (ammonium) has one mole of nitrogen atoms and four moles of hydrogen atoms, for a total of five moles of atoms. Multiply by Avogadro's Number to convert moles of atoms to atoms.
What is the mass percent of nitrogen in ammonium carbonate?
The molecular formula of ammonium carbonate is (NH4)2CO3. The molar mass of nitrogen in ammonium carbonate is 28.02 g/mol. The molar mass of ammonium carbonate is 96.09 g/mol. To calculate the mass percent of nitrogen in ammonium carbonate, you would divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100. This gives a mass percent of nitrogen in ammonium carbonate of around 29.1%.
How many grams of nitrogen are there in NH4NO3?
Firstly, find the percent composition of hydrogen in the compound (ammonium nitrate). So we have: 2 x Nitrogen atom = 28.02 amu 4 x Hydrogen atoms = 4.04 amu 3 x Oxygen atoms = 48.00 amu Total of: 80.06 amu or g/mol % H = 4.04 g/mol ÷ 80.06 g/mol = 0.050462153385 = 5.05 % (sig. figs.) Then, we take the percentage of hydrogen and multiply it by the mass of the substance. 50.00 g NH4NO3 x 0.050462153385 = 2.52310766925 = 2.52 g H So, there is 2.52 g of hydrogen in 50.00 g of NH4NO3
What is the mass percent of nitrogen in ammonium carbonate (NH4)2CO3?
To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.
