0
Firstly, find the percent composition of hydrogen in the compound (ammonium nitrate).
So we have:
2 x Nitrogen atom = 28.02 amu
4 x Hydrogen atoms = 4.04 amu
3 x Oxygen atoms = 48.00 amu
Total of: 80.06 amu or g/mol
% H = 4.04 g/mol ÷ 80.06 g/mol = 0.050462153385 = 5.05 % (sig. figs.)
Then, we take the percentage of hydrogen and multiply it by the mass of the substance.
50.00 g NH4NO3 x 0.050462153385 = 2.52310766925 = 2.52 g H
So, there is 2.52 g of hydrogen in 50.00 g of NH4NO3
What else can I help you with?
How many grams of NH4NO3 would be required to prepare 0.500 L of a solution that is 0.450 M in NH4NO3(aq)?
NH4NO3's molar mass = 80.0gMolarity = moles of solute / liters of solution0.450 M = X / 0.500 LX = .225 molesNow we must convert X to grams because it is currently in moles.(.225 moles) / 1 * ( 80.0 grams ) / 1 mole =18 grams of NH4NO3
What is the percent nitrogen in NH4NO3?
The percent nitrogen in NH4NO3 is 35.04%. This can be calculated by dividing the molar mass of nitrogen in the compound by the molar mass of the entire compound and then multiplying by 100.
What is the correct formula for ammonium nitrogen trioxide?
Formula: NH4NO3 It is actually Ammonium Nitrate
How many atoms are there in NH4NO3?
There are a total of 26 atoms in one molecule of NH4NO3. This includes 2 nitrogen atoms, 4 hydrogen atoms, and 3 oxygen atoms.
How many atoms of nitrogen are in 20g of NH4NO3?
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
How many g of nitrogen are in 35.8kg of ammonium nitrate?
To calculate the amount of nitrogen in ammonium nitrate, we first need to determine its molecular formula, which is NH4NO3. This means that there is one nitrogen atom in each molecule. One mole of NH4NO3 weighs approximately 80 grams, and contains one mole of nitrogen which weighs about 14 grams. To find the amount of nitrogen in 35.8 kg of ammonium nitrate, we can set up a simple proportion: (35.8 kg / 80 kg) * 14 g = 6.29 g of nitrogen.
How many atoms of nitrogen are in 10g of NH4NO3?
One mole of NH4 (ammonium) has one mole of nitrogen atoms and four moles of hydrogen atoms, for a total of five moles of atoms. Multiply by Avogadro's Number to convert moles of atoms to atoms.
How many grams of NH4NO3 would be required to prepare 0.500 L of a solution that is 0.450 M in NH4NO3(aq)?
NH4NO3's molar mass = 80.0gMolarity = moles of solute / liters of solution0.450 M = X / 0.500 LX = .225 molesNow we must convert X to grams because it is currently in moles.(.225 moles) / 1 * ( 80.0 grams ) / 1 mole =18 grams of NH4NO3
What is the percent nitrogen in NH4NO3?
The percent nitrogen in NH4NO3 is 35.04%. This can be calculated by dividing the molar mass of nitrogen in the compound by the molar mass of the entire compound and then multiplying by 100.
The percent by mass of nitrogen in NH4NO3 is closest to?
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
What is the correct formula for ammonium nitrogen trioxide?
Formula: NH4NO3 It is actually Ammonium Nitrate
Which among the compounds has the highest amount of nitrogen n2o srno32 nh4no3 hno3?
N2O is the compounds with the highest amount of nitrogen than the srno32, nh4no3 and hno3.
How many atoms are there in NH4NO3?
There are a total of 26 atoms in one molecule of NH4NO3. This includes 2 nitrogen atoms, 4 hydrogen atoms, and 3 oxygen atoms.
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many atoms of nitrogen are in 20g of NH4NO3?
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
How many moles of nitrogen are in 15 grams of nitrogen?
15 grams of nitrogen are equal to 1,071 moles.
What elements are in NH4NO3?
The chemical name for NH4NO3 is ammonium nitrate. Ammonium nitrate is composed of the elements nitrogen (N), hydrogen (H) and oxygen (O). NH4NO3 has a molecular weight of 80.05-grams per mole.
