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Firstly, find the percent composition of hydrogen in the compound (ammonium nitrate).
So we have:
2 x Nitrogen atom = 28.02 amu
4 x Hydrogen atoms = 4.04 amu
3 x Oxygen atoms = 48.00 amu
Total of: 80.06 amu or g/mol
% H = 4.04 g/mol ÷ 80.06 g/mol = 0.050462153385 = 5.05 % (sig. figs.)
Then, we take the percentage of hydrogen and multiply it by the mass of the substance.
50.00 g NH4NO3 x 0.050462153385 = 2.52310766925 = 2.52 g H
So, there is 2.52 g of hydrogen in 50.00 g of NH4NO3
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How many grams of NH4NO3 would be required to prepare 0.500 L of a solution that is 0.450 M in NH4NO3(aq)?
NH4NO3's molar mass = 80.0gMolarity = moles of solute / liters of solution0.450 M = X / 0.500 LX = .225 molesNow we must convert X to grams because it is currently in moles.(.225 moles) / 1 * ( 80.0 grams ) / 1 mole =18 grams of NH4NO3
How many moles of nitrogen gas are produced when ammonium nitrate reacts?
1 mole of ammonium nitrate produces one mole of nitrogen. Actually the amount (in moles) of nitrogen will depend on how much NH4NO3 you are starting with, what other reactant you are combining it with and whether or not the NH4NO3 completely reacts. Since you will never be able to retrieve all of the nitrogen (either the NH4 or the NO3 will retain some nitrogen depending upon the reaction), you can reasonably expect to get 1 mole of N2 for each 14.01 grams of Ammonium nitrate that COMPLETELY reacts.
What elements are in NH4NO3?
The chemical name for NH4NO3 is ammonium nitrate. Ammonium nitrate is composed of the elements nitrogen (N), hydrogen (H) and oxygen (O). NH4NO3 has a molecular weight of 80.05-grams per mole.
What is the correct formula for ammonium nitrogen trioxide?
Formula: NH4NO3 It is actually Ammonium Nitrate
What is the oxidation number for NH4NO3?
This is a ionic compound. nitrogen shows -3 and =5 in this compound.
How many atoms of nitrogen are in 10g of NH4NO3?
One mole of NH4 (ammonium) has one mole of nitrogen atoms and four moles of hydrogen atoms, for a total of five moles of atoms. Multiply by Avogadro's Number to convert moles of atoms to atoms.
How many grams of NH4NO3 would be required to prepare 0.500 L of a solution that is 0.450 M in NH4NO3(aq)?
NH4NO3's molar mass = 80.0gMolarity = moles of solute / liters of solution0.450 M = X / 0.500 LX = .225 molesNow we must convert X to grams because it is currently in moles.(.225 moles) / 1 * ( 80.0 grams ) / 1 mole =18 grams of NH4NO3
Which among the compounds has the highest amount of nitrogen n2o srno32 nh4no3 hno3?
N2O is the compounds with the highest amount of nitrogen than the srno32, nh4no3 and hno3.
How many moles of nitrogen gas are produced when ammonium nitrate reacts?
1 mole of ammonium nitrate produces one mole of nitrogen. Actually the amount (in moles) of nitrogen will depend on how much NH4NO3 you are starting with, what other reactant you are combining it with and whether or not the NH4NO3 completely reacts. Since you will never be able to retrieve all of the nitrogen (either the NH4 or the NO3 will retain some nitrogen depending upon the reaction), you can reasonably expect to get 1 mole of N2 for each 14.01 grams of Ammonium nitrate that COMPLETELY reacts.
The percent by mass of nitrogen in NH4NO3 is closest to?
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
How many g of nitrogen are in 35.8kg of ammonium nitrate?
Mass(g)of N = 35.8 g NH4NO3 X 28 g of N / 80 g NH4NO3 = 12.53 g N
How many moles of nitrogen are in 15 grams of nitrogen?
15 grams of nitrogen are equal to 1,071 moles.
What elements are in NH4NO3?
The chemical name for NH4NO3 is ammonium nitrate. Ammonium nitrate is composed of the elements nitrogen (N), hydrogen (H) and oxygen (O). NH4NO3 has a molecular weight of 80.05-grams per mole.
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many moles of nitrogen are there in 29 grams of nitrogen?
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
How many atoms are represented in the formula for ammonium nitrate?
9 atoms Here is the formula for ammonium nitrate. NH4NO3 This shows there are two nitrogen atoms, 4 hydrogen, and 3 oxygen. So 1 (nitrogen) + 1(nitrogen) + 4(hydrogen) + 3(oxygen) = 9 atoms
What is the oxidation number for NH4NO3?
This is a ionic compound. nitrogen shows -3 and =5 in this compound.
