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Mass(g)of N = 35.8 g NH4NO3 X 28 g of N / 80 g NH4NO3 = 12.53 g N

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Q: How many g of nitrogen are in 35.8kg of ammonium nitrate?
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How many atoms are present in ammonium nitrate?

the only What elements are in ammonium? Elements in aluminum nitrate? What elements are in ammonium nitrate? How many elements in ammonium nitrate? How many elements are in ammonium nitrate? What elements are present in Sodium Nitrate? What elements are present in SSodium Nitrate? How many elements are there in Ammonium nitrate? How many elements are present in ammonium nitrate? What elements make up the compound ammonium nitrate? How many of each atom is present in ammonium nitrate? What is the dissociation reaction for ammonium nitrate? How many different elements are there in amonium nitrate? How many different elements are there in ammonium nitrate? How mant different elements are present in ammoniumnirate? Hhow many different elements are present in amonium nitrate? How many atoms are present in the formula of ammonium nirate? How many different elements are presented in ammonium mitrate? How many different elements are presented in ammonium nitrate? What is the percent composition of the elements in ammonium sulfite?


How many moles of nitrogen are there in 3 moles of ammonium nitrate?

The volume occupied by 3 moles of nitrogen gas will be different, depending on the temperature and pressure of the gas.


How many grams of nitrogen are in 48.5g ammonium nitrate?

Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.


How many atoms are represented in the formula for ammonium nitrate?

9 atoms Here is the formula for ammonium nitrate. NH4NO3 This shows there are two nitrogen atoms, 4 hydrogen, and 3 oxygen. So 1 (nitrogen) + 1(nitrogen) + 4(hydrogen) + 3(oxygen) = 9 atoms


How many mole is 8.0g of ammonium nitrate?

1 mole of Ammonium Nitrate= 80g (R.A.M of compound) Therefore 8g of Ammonium nitrate= 8g/80g= 0.1 mole (moles = mass given over molar mass)

Related questions

How many atoms are present in ammonium nitrate?

the only What elements are in ammonium? Elements in aluminum nitrate? What elements are in ammonium nitrate? How many elements in ammonium nitrate? How many elements are in ammonium nitrate? What elements are present in Sodium Nitrate? What elements are present in SSodium Nitrate? How many elements are there in Ammonium nitrate? How many elements are present in ammonium nitrate? What elements make up the compound ammonium nitrate? How many of each atom is present in ammonium nitrate? What is the dissociation reaction for ammonium nitrate? How many different elements are there in amonium nitrate? How many different elements are there in ammonium nitrate? How mant different elements are present in ammoniumnirate? Hhow many different elements are present in amonium nitrate? How many atoms are present in the formula of ammonium nirate? How many different elements are presented in ammonium mitrate? How many different elements are presented in ammonium nitrate? What is the percent composition of the elements in ammonium sulfite?


How many different elemnts in ammonium nitrate?

The chemical formula for ammonium nitrate is NH4NO3. It consists of 3 elements: nitrogen, hydrogen and oxygen.


How many moles of nitrogen are there in 3 moles of ammonium nitrate?

The volume occupied by 3 moles of nitrogen gas will be different, depending on the temperature and pressure of the gas.


How many grams of nitrogen are in 48.5g ammonium nitrate?

Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.


How many moles of nitrogen gas are produced when ammonium nitrate reacts?

1 mole of ammonium nitrate produces one mole of nitrogen. Actually the amount (in moles) of nitrogen will depend on how much NH4NO3 you are starting with, what other reactant you are combining it with and whether or not the NH4NO3 completely reacts. Since you will never be able to retrieve all of the nitrogen (either the NH4 or the NO3 will retain some nitrogen depending upon the reaction), you can reasonably expect to get 1 mole of N2 for each 14.01 grams of Ammonium nitrate that COMPLETELY reacts.


How many atoms are represented in the formula for ammonium nitrate?

9 atoms Here is the formula for ammonium nitrate. NH4NO3 This shows there are two nitrogen atoms, 4 hydrogen, and 3 oxygen. So 1 (nitrogen) + 1(nitrogen) + 4(hydrogen) + 3(oxygen) = 9 atoms


How many elememts in ammonium nitrate?

Ammonium nitrate(NH4NO3) composition:Nitrogen = 2 atomsOxygen = 3 atomsHydrogen = 4 atoms


How many units of urea are in 1 ton?

Urea is 46-0-0, and ammonium nitrate is 34-0-0. Both of these products contain nothing but nitrogen, but the nitrogen is at different percentages. Urea contains 920 actual pounds of nitrogen per ton, and ammonium nitrate contains 680 actual pounds of nitrogen by ton (2,000 x 46% = 920 and 2,000 x 34% = 680)


How many atoms are present in the formula of ammoium nitrate?

Nine atoms represent the empirical formula of ammonium nitrate. Namely, 2 nitrogen atoms, 3 oxygen atoms and 4 hydrogen atoms.


How many mole is 8.0g of ammonium nitrate?

1 mole of Ammonium Nitrate= 80g (R.A.M of compound) Therefore 8g of Ammonium nitrate= 8g/80g= 0.1 mole (moles = mass given over molar mass)


How many elements are there in one molecule in ammonium nitrate?

2


How many moles is 8.0g of ammonium nitrate?

0.0999458293608 moles