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The percent by mass of nitrogen in NH4NO3 is closest to?

Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%


What is the percent composition of ammonium carbonate?

Ammonium carbonate has the formula (NH4)2CO3. To calculate the percent composition, you first find the molar mass of each element and then divide the molar mass of each element in the formula by the formula mass of the compound and multiply by 100 to get the percentage.


What is the mass percent of n in ammonium bicarbonate?

The formula for ammonium bicarbonate is NH4HCO3. To find the mass percent of nitrogen (N), calculate the molar mass of nitrogen in the formula and divide it by the molar mass of the entire compound NH4HCO3. The molar mass of N is 14.01 g/mol, and the molar mass of NH4HCO3 is 79.06 g/mol. Therefore, the mass percent of nitrogen in ammonium bicarbonate is (14.01 g/mol / 79.06 g/mol) * 100% = 17.7%.


How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?

To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.


How many moles of ammonium ions are in 8.754g of ammonium carbonate?

To calculate the number of moles of ammonium ions in 8.754g of ammonium carbonate, first find the molar mass of ammonium carbonate [(NH₄)₂CO₃] which is 96.09 g/mol. Next, find the moles of ammonium carbonate by dividing the given mass by the molar mass. There are 0.0913 moles of (NH₄)₂CO₃ in 8.754g. Since there are 2 ammonium ions in 1 molecule of ammonium carbonate, there are 0.1826 moles of ammonium ions in 8.754g of ammonium carbonate.

Related Questions

What is the mass percent of nitrogen in ammonium carbonate (NH and Aacute) and iquestCO and Agrave?

The molar mass of ammonium carbonate is 96 g/mol (NH4)2CO3. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the mass percent of nitrogen in ammonium carbonate is (2*14 g/mol / 96 g/mol) * 100% = 29.2%.


What is the mass percent of nitrogen in ammonium carbonate (NH4)2CO3?

To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.


What is the mass percent of nitrogen in ammonia carbonate (NH4)2CO3?

To calculate the mass percent of nitrogen in ammonium carbonate ((NH4)2CO3), first find the molar mass of the compound: (2 x 14) + 12 + 3 x 16 = 96 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. The mass percent of nitrogen in (NH4)2CO3 is (2 x 14) / 96 x 100 = 29.2%.


The percent by mass of nitrogen in NH4NO3 is closest to?

Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%


What is the percent on nitrogen in ammonium hydrogen sulfate?

Ammonium hydrogen sulfate, (NH4)HSO4, contains one nitrogen atom in the ammonium ion. To calculate the percentage of nitrogen by mass, you would find the molar mass of nitrogen in the compound and divide it by the molar mass of the entire compound, then multiply by 100 to get the percentage.


What is the percent composition of ammonium carbonate?

Ammonium carbonate has the formula (NH4)2CO3. To calculate the percent composition, you first find the molar mass of each element and then divide the molar mass of each element in the formula by the formula mass of the compound and multiply by 100 to get the percentage.


How many moles of nitrogen are in 650 moles of ammonium carbonate How many grams of this compound supply this much nitrogen?

The formula unit for the usual form of solid ammonium carbonate is (NH4)2CO3.H2O. This formula shows that each formula unit contains two atoms of nitrogen. Because nitrogen forms diatomic molecules at standard temperature and pressure, the number of moles of nitrogen is therefore the same as the number of formula units of ammonium carbonate, stated to be 650. The gram formula unit mass of this solid ammonium carbonate is 114.10. Therefore, 114.10(650) or 7.42 X 103 grams of the solid, to the justified number of significant digits, will be required.


What is the mass percent of n in ammonium bicarbonate?

The formula for ammonium bicarbonate is NH4HCO3. To find the mass percent of nitrogen (N), calculate the molar mass of nitrogen in the formula and divide it by the molar mass of the entire compound NH4HCO3. The molar mass of N is 14.01 g/mol, and the molar mass of NH4HCO3 is 79.06 g/mol. Therefore, the mass percent of nitrogen in ammonium bicarbonate is (14.01 g/mol / 79.06 g/mol) * 100% = 17.7%.


Determine both the formula mass and molar mass of ammonium carbonate?

The formula mass of ammonium carbonate (NH4)2CO3 is 96.09 g/mol. Since the formula contains two ammonium ions, the molar mass of ammonium carbonate is 96.09 g/mol * 2 = 192.18 g/mol.


How many moles of ammonium ions are in 8.738 g of ammonium carbonate?

To determine the number of moles of ammonium ions in 8.738 g of ammonium carbonate, first calculate the molar mass of ammonium carbonate (NH4)2CO3. Then, divide the given mass by the molar mass to find the number of moles. Since there are two ammonium ions in one formula unit of ammonium carbonate, multiply the number of moles by 2 to get the moles of ammonium ions.


How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?

To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.


How many moles of ammonium ions are in 8.903 g of ammonium carbonate?

The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.