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Question : How many moles of ammonium ions are in 8.754g of ammonium carbonate?
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- Let's use the criss-cross method: (NH4+, CO32-)→(NH4)2CO3
- That menas in each mole of ammonium carbonate((NH4)2CO3 )there are 2moles of ammonium (NH4).
- Let's find the quantity of mole(N) in 8.75g of ammonium carbonate((NH4)2CO3 ).
- N=mass/Molar mass (#)
- Molar mass((NH4)2CO3 )=2(14.0067+41.0079)+12.011+315.999)g/mol=96.09g/mol.
- (#) Gives us : N=(8.754g)/(96.09g/mol)=0.0911mole
- Let's K be the quantity of ammonium mole included in 8.75g of ammonium carbonate. As I stated before each mole of ammonium carbonate contains 2moles of ammonium, therefore : K=2*0.0911mole=1.1822mole
- Best regards,
- BILL JESY FOREVER 7171.
What else can I help you with?
How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?
To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.
How many moles of ammonium ions are in 6.965 of ammonium carbonate?
To find the number of moles of ammonium ions, we first calculate the molar mass of ammonium carbonate (NH4)2CO3. It is 96.086 g/mol. Then we can find the moles of (NH4)2 cations in 6.965 g by dividing the mass by the molar mass. This gives us 0.0726 moles of ammonium ions.
How many moles of ammonium ions are in 8.790g of ammonium carbonate?
Ammonium carbonate is (NH4 )2 CO3 and the molar mass is 96.0878 so you just divide 8.790 g/96.0878 and you get 0.91478835 and since there are two ammonium (NH4 )2 ions you multiply 0.91478835 * 2 and get 0.1830 mol.
How many moles of ammonium ions are in 6.965 g of ammonium carbonate?
To find the number of moles of ammonium ions in 6.965 g of ammonium carbonate, you first need to calculate the molar mass of ammonium ions, which is 18.0399 g/mol. Then, divide the given mass by the molar mass to find the number of moles. So, 6.965 g / 18.0399 g/mol = 0.386 moles of ammonium ions.
How many moles of ammonium ions are in 4.50 mol NH4 2CO3?
There are 4.50 moles of NH4 2CO3 in 4.50 mol NH4 2CO3. Since each formula unit of NH4 2CO3 contains 2 moles of ammonium ions (NH4+), there would be 2 * 4.50 = 9.00 moles of ammonium ions in 4.50 mol NH4 2CO3.
How many moles of ammonium ions are in 8.738 g of ammonium carbonate?
To determine the number of moles of ammonium ions in 8.738 g of ammonium carbonate, first calculate the molar mass of ammonium carbonate (NH4)2CO3. Then, divide the given mass by the molar mass to find the number of moles. Since there are two ammonium ions in one formula unit of ammonium carbonate, multiply the number of moles by 2 to get the moles of ammonium ions.
How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?
To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.
How many moles of ammonium ions are in 6.965 of ammonium carbonate?
To find the number of moles of ammonium ions, we first calculate the molar mass of ammonium carbonate (NH4)2CO3. It is 96.086 g/mol. Then we can find the moles of (NH4)2 cations in 6.965 g by dividing the mass by the molar mass. This gives us 0.0726 moles of ammonium ions.
How many moles of ammonium ions are in 8.718 g of ammonium carbonate?
To find the number of moles of ammonium ions in 8.718 g of ammonium carbonate, we first calculate the molar mass of ammonium carbonate [(NH4)2CO3] which is 96.09 g/mol. Next, we convert the given mass to moles using the formula: moles = mass/molar mass. Thus, there are approximately 0.0907 moles of ammonium ions in 8.718 g of ammonium carbonate.
How many moles of ammonium ions are in 8.790g of ammonium carbonate?
Ammonium carbonate is (NH4 )2 CO3 and the molar mass is 96.0878 so you just divide 8.790 g/96.0878 and you get 0.91478835 and since there are two ammonium (NH4 )2 ions you multiply 0.91478835 * 2 and get 0.1830 mol.
How many moles of ammonium ions are in 8.903 g of ammonium carbonate?
The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.
How many moles of ammonium ions are in 6.965 g of ammonium carbonate?
To find the number of moles of ammonium ions in 6.965 g of ammonium carbonate, you first need to calculate the molar mass of ammonium ions, which is 18.0399 g/mol. Then, divide the given mass by the molar mass to find the number of moles. So, 6.965 g / 18.0399 g/mol = 0.386 moles of ammonium ions.
How many moles of ammonium ions are in 8.778 of ammonium carbonate?
assuming that 8.778 is in grams then there are 0.1069 moles in 8.778 grams of ammonium carbonate here is the math:(NH4)2CO3 N2=14.01g H8=8.08g C=12.01g O3=48.00 14.01+8.08+12.01+48.00=82.10g/mole 8.778g X 1 mole/82.10g=0.1069moles
Would an aqueous solution of Ammonium Carbonate Contain Ions?
Yes. An aqueous solution of ammonium carbonate would consist of dissociated ammonium ions and carbonate ions.
How many moles of ammonium ions are in 4.50 mol NH4 2CO3?
There are 4.50 moles of NH4 2CO3 in 4.50 mol NH4 2CO3. Since each formula unit of NH4 2CO3 contains 2 moles of ammonium ions (NH4+), there would be 2 * 4.50 = 9.00 moles of ammonium ions in 4.50 mol NH4 2CO3.
Is ammonium carbonate an insoluble salt?
yes Ammonium carbonate is soluble in water.
What is the ionic compounds of ammonium carbonate?
(NH4)2CO3----------------------Ammonium carbonate
