Here is the solution,
for 1mole NH3 or ammonia,
N: 14.0067 g/mol x 1
H: 1.00794 g/mol x 3
So approximately it is--> 17.03052 g/mol)
Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g
45/94.2 is 0.4777 moles
That is 45 teaspoons.
1.5873283 ouncesHere is the formula in case you are interested -45 g*1 oz28.34952313 g=1.587328288 oz
5 grams of water is approximately 1.5 ounces
The moles number of water 12; the chemical formula is KAl(SO4)2.12H2O.
45/94.2 is 0.4777 moles
To calculate the number of grams in 2.50 moles of H2O, you first need to know the molar mass of water (H2O), which is approximately 18.015 g/mol. Then, you can use the formula: grams = moles x molar mass. So, 2.50 moles of H2O is equivalent to 45.04 grams (2.50 moles x 18.015 g/mol).
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
To find the number of atoms in 45 grams of Pb (lead), we need to first calculate the number of moles. The molar mass of Pb is approximately 207.2 g/mol. By dividing the given mass by the molar mass, we can find the number of moles. Then, we can convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol).
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
45 g water are obtained.
There's a thousand grams in a kilogram, 45 grams is 0.045 kilograms.
0.045 grams is 45 milligrams.
450 grams
1kg = 1000g. Therefore, 45 x 1000 = 45000 grams.
6.25 kg/45 litres = 6250 grams/45 litres = 6250/45 grams per litre =138.88... gpl
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