45/94.2 is 0.4777 moles
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
75 grams water is equal to 4,166 moles.
According to the reaction (4 \text{K} + \text{O}_2 \rightarrow 2 \text{K}_2\text{O}), 4 moles of potassium produce 2 moles of potassium oxide (K2O). Thus, the mole ratio of potassium to K2O is 4:2, or 2:1. If 1.52 moles of potassium are used, the number of moles of K2O formed can be calculated as (1.52 , \text{moles K} \times \frac{2 , \text{moles K2O}}{4 , \text{moles K}} = 0.76 , \text{moles K2O}). Therefore, 0.76 moles of potassium oxide will be formed.
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
Potassium oxide violently react with water !
34,7 moles of potassium 1 356,7 g.
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
3.99 or 4
75 grams water is equal to 4,166 moles.
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
242.594 g
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
According to the reaction (4 \text{K} + \text{O}_2 \rightarrow 2 \text{K}_2\text{O}), 4 moles of potassium produce 2 moles of potassium oxide (K2O). Thus, the mole ratio of potassium to K2O is 4:2, or 2:1. If 1.52 moles of potassium are used, the number of moles of K2O formed can be calculated as (1.52 , \text{moles K} \times \frac{2 , \text{moles K2O}}{4 , \text{moles K}} = 0.76 , \text{moles K2O}). Therefore, 0.76 moles of potassium oxide will be formed.