75 grams water is equal to 4,166 moles.
45/94.2 is 0.4777 moles
1,4 moles of lead(II) oxide are formed.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
Dihydrogen oxide
To find the number of moles of nitrogen in 90.0 grams of nitrous oxide (N₂O), first determine the molar mass of N₂O, which is approximately 44.01 g/mol (14.01 g/mol for nitrogen and 16.00 g/mol for oxygen). The number of moles of N₂O in 90.0 grams is calculated as 90.0 g / 44.01 g/mol ≈ 2.05 moles of N₂O. Since each molecule of N₂O contains one nitrogen atom, there are also approximately 2.05 moles of nitrogen in 90.0 grams of nitrous oxide.
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
45/94.2 is 0.4777 moles
62 grams a+
To find the mole fraction of nitric oxide, first calculate the moles of nitric oxide and oxygen gas separately by dividing the given mass by their respective molar masses. Then, find the total moles of both gases present in the mixture. Finally, divide the moles of nitric oxide by the total moles to calculate its mole fraction.
1,4 moles of lead(II) oxide are formed.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.
To find the mass of sodium oxide formed, we first need to calculate the moles of sodium used, which is 0.3 moles (6.9g / 23g/mol). Since one mole of sodium reacts with one mole of oxygen to form sodium oxide, the moles of sodium oxide formed is also 0.3 moles. The molar mass of sodium oxide (Na2O) is 62g/mol. Therefore, the mass of sodium oxide formed is 18.6 grams (0.3 moles * 62g/mol).
Dihydrogen oxide
46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.