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46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.

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Sodium will react with oxygen to form sodium oxide Use the formula below to determine how many grams of sodium oxide will be formed if 46 grams of sodium are used in the reaction?

The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.


How many grams of sodium oxide will be formed is 46 grams of sodium are used in the reaction?

If the reaction is:6 Na + 2 O2 = 2 Na2O + Na2O2This mass is 3,83 g sodium.


Sodium will react with oxygen to form sodium oxide. Use the formula below to determine how many grams of sodium oxide will be formed if 46 grams of sodium are used in the reaction.?

62 grams a+


Sodium oxide and water react to produce sodium hydroxide. How many grams of sodium hydroxide is produced from 120.0g of sodium oxide?

155.2 g


How many grams of sodium oxide will be formed if 46 grams of sodium are used in 4Na plus O2 2NaO?

Since the balanced equation is 4Na + O2 -> 2NaO, the molar ratio between Na and NaO is 4:2 or 2:1. This means that for every 2 moles of Na used, 1 mole of NaO is formed. The molar mass of NaO is 62 g/mol. Therefore, if 46 grams of sodium are used, then 31 grams of sodium oxide will be formed.


If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?

To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.


When 46g of sodium were exposed to dry air 62g of sodium oxide formed how many grams of oxygen from the air were used?

To find the amount of oxygen used, we need to consider the difference in mass between sodium and sodium oxide. The mass increase is 16g (62g - 46g) which corresponds to the amount of oxygen used from the air. Therefore, 16g of oxygen from the air were used.


How many grams of aluminum oxide can be formed by the reaction of 1020g of aluminum with oxygen?

To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.


How many grams of oxygen gas are required to react completely with 14.6 grams of solid sodium to form sodium oxide?

Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------


How many elements are in sodium oxide?

There are two elements, namely sodium and oxygen.


How many grams of sodium are in sodium carbonate?

There are 2.54 grams of sodium in 1 gram of sodium carbonate.


How many grams of ammonia are consumed in the reaction of 75.0g lead (II) oxide?

The complete question: Lead (II) oxide reacts with ammonia forming solid lead nitrogen gas and liquid water. 1.)How many grams of ammonia are consumed in the reaction of 75.0g lead (II) oxide? 2.) If 56.4g of lead are produced how many grams of nitrogen are also formed?