16 grams? I would purpose that this has a little something to do with the law on conservation of mass.
I could always be wrong though...
The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.
Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------
62 grams a+
To find the grams of sodium formed, we need to first determine the molar mass of Na3N, which is 84 g/mol. From the balanced equation, we see that for every 2 moles of Na3N that decompose, 6 moles of sodium are formed. Therefore, using the molar mass of Na (23 g/mol), we can calculate that 100.0 grams of Na3N would produce 85.71 grams of sodium.
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.
To find the mass of sodium oxide formed, we first need to calculate the moles of sodium used, which is 0.3 moles (6.9g / 23g/mol). Since one mole of sodium reacts with one mole of oxygen to form sodium oxide, the moles of sodium oxide formed is also 0.3 moles. The molar mass of sodium oxide (Na2O) is 62g/mol. Therefore, the mass of sodium oxide formed is 18.6 grams (0.3 moles * 62g/mol).
Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------
62 grams a+
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
The percentage of oxygen is 54,84 %.
If the reaction is:6 Na + 2 O2 = 2 Na2O + Na2O2This mass is 3,83 g sodium.
25
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
To find the grams of sodium formed, we need to first determine the molar mass of Na3N, which is 84 g/mol. From the balanced equation, we see that for every 2 moles of Na3N that decompose, 6 moles of sodium are formed. Therefore, using the molar mass of Na (23 g/mol), we can calculate that 100.0 grams of Na3N would produce 85.71 grams of sodium.