First take the molecular mass.Just multiply 2.33 by it
To convert moles of CH4 (methane) to grams, you would use the molar mass of CH4, which is approximately 16.04 g/mol. Multiply the number of moles of CH4 by this molar mass to obtain the mass in grams. The formula is: grams of CH4 = moles of CH4 × 16.04 g/mol.
Two moles of water are produced.
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
It is just as the number.It has 6.5 moles in it
It depends on temperature,pressure and volume.THese are needed to find number of moles
To convert moles of CH4 (methane) to grams, you would use the molar mass of CH4, which is approximately 16.04 g/mol. Multiply the number of moles of CH4 by this molar mass to obtain the mass in grams. The formula is: grams of CH4 = moles of CH4 × 16.04 g/mol.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
There are 0.75 moles in it.You have to devide 12 by molecular mass
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
Two moles of water are produced.
I. False - Since both gases contribute to the total mass, the number of moles of NO does not necessarily need to be greater than the number of moles of CH4. II. True - If the total mixture mass is 17 grams and CH4 is 8 grams, then the remaining mass must be of NO. III. True - If the total moles of the mixture is 0.8, and CH4 is 0.5 moles (8g/16 g/mol), then the moles of NO would be the remaining 0.3 moles.
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
This mass is 6,416 g.
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.