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For this you need the Atomic Mass of Cr. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel.
11.9 moles Cr × (52.0 grams) =618.8 grams Cr
What else can I help you with?
How many atoms are presents in 3 moles of chromium?
1.8x10*24
How many miles of calcium nitrate would react with 4.55 moles of Chromium (III) sulfate to produce chromium (III) nitrate?
To determine how many miles of calcium nitrate would react with 4.55 moles of Chromium (III) sulfate to produce chromium (III) nitrate, you would first need to write the balanced chemical equation for the reaction between calcium nitrate and chromium (III) sulfate. Then, use the stoichiometry of the reaction to convert moles of Chromium (III) sulfate to moles of calcium nitrate, and finally, convert moles of calcium nitrate to miles using the molar mass.
How many moles are in 119 grams of uranium?
To find the number of moles in 119 grams of uranium, you need to divide the given mass by the molar mass of uranium. The molar mass of uranium is approximately 238.03 grams/mol. Dividing 119 grams by 238.03 grams/mol gives you 0.5 moles of uranium.
How many gmole of chromium II hydroxide?
To calculate the number of grams-moles (gmole) of chromium(II) hydroxide, you need to know the mass of chromium(II) hydroxide in grams and its molar mass. Once you have these values, you can use the formula: gmole = mass (in grams) / molar mass.
How many grams of potassium bromite (KBrO2) are there in 0.280 moles?
To calculate the grams of potassium bromite in 0.280 moles, you would multiply the number of moles by the molar mass of KBrO2, which is 119 g/mol. Therefore, 0.280 moles of KBrO2 would be 0.280 moles * 119 g/mol = 33.32 grams.
A stock solution of chromium was prepared by dissolving 414.4mg K2cro4 in 0.1l water. What is the concentration of chromium in this stock solution in ppm?
The molar mass of K2CrO4 is 294.18 g/mol. Therefore, the number of moles of K2CrO4 in 414.4 mg is 0.00141 mol. As there are 2 moles of chromium in 1 mole of K2CrO4, the number of moles of chromium is 0.00282 mol. The concentration of chromium in the stock solution is 28,200 ppm.
How many moles of hydrogen are need to convert 5 moles of chromium oxide?
The balanced chemical equation for this reaction is: Cr2O3 + 3H2 -> 2Cr + 3H2O. So, according to the equation, 3 moles of hydrogen are needed to convert 1 mole of chromium oxide. Therefore, to convert 5 moles of chromium oxide, 15 moles of hydrogen would be needed.
How many moles of Cr are there in a sample of Cr that contains 4.37E 23 atoms?
To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.
What is the molality of a solid solution containing 0.125 g of chromium and 81.3 grams of iron?
To calculate the molality of the solid solution, you need to first find the moles of chromium and iron separately. Then, determine the total moles of solute (chromium) and solvent (iron). Finally, divide the moles of solute by the mass of the solvent (in kg) to get the molality. Molality (m) = moles of solute / mass of solvent (kg).
How many moles are present in260g of chromium?
To find the number of moles in 260g of chromium, you need to divide the given mass by the molar mass of chromium. The molar mass of chromium is approximately 51.996 g/mol. Dividing 260g by the molar mass gives you about 5 moles of chromium.
If a compound containing chromium and silicon has 73.52 mass percent chromium what is its empirical formula?
To find the empirical formula, we need to determine the molar ratio of chromium to silicon. If 73.52% of the compound's mass is chromium, then the mass of silicon must be 100% - 73.52% = 26.48%. Next, we convert these percentages to moles, then divide by the smallest number of moles to get the simplest whole number ratio. The empirical formula is CrSi.
How many moles are contained in 22.23 g KBr?
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
