A "mole" of chromium is generally regarded as consisting of
Avogadro's Number of atoms. Therefore, 4.37 X 1023 atoms
constitutes (4.37 X 1023)/(6.022 X 1023) or 0.726 moles.
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Q: How many moles of Cr are there in a sample of Cr that contains 4.37E 23 atoms?