1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
The molar mass of HF (hydrofluoric acid) is 20.01 g/mol. Therefore, 3 moles of HF would be equal to 60.03 grams.
There are about 38.58 pw in 60 grams.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
You have to know the concentration first. That will either be in grams per milliliter (or milligrams per milliliter), or it could be in moles per liter (molarity). If it's given in grams per milliliter, just multiply that number by 60 and multiply by 1000.If it's given in moles per liter, than first find how many moles in 60 mL by multiplying by 0.06, and then convert moles to grams using the molar mass of caffeine (194.19 grams per mole).See the Related Questions for how to convert moles to grams.
To find the number of moles, we need to convert the given mass in grams to moles. The molar mass of silicon dioxide (SiO2) is approximately 60 grams/mol. Number of moles = (3.4x10^-7 grams) / (60 grams/mol) = 5.7x10^-9 moles.
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
The molar mass of HF (hydrofluoric acid) is 20.01 g/mol. Therefore, 3 moles of HF would be equal to 60.03 grams.
There are about 38.58 pw in 60 grams.
60 milligrams = 0.06 grams
60kgs = 60,000 grams.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
60 grammes = 0.06 kilogrammes