2.5 moles H2O (2 moles H/1 mole H2O)
= 5 moles of hydrogen
For this you need the atomic (molecular) mass of H2O. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. H2O= 18.0 grams2.5 moles H2O × (18.0 grams) = 45.0 grams H2O
To determine how many hydrogen atoms are in 301 grams of H2O, we need to consider the molar mass of water (H2O). The molar mass of water is approximately 18 grams/mole. Since the molecular formula of water is H2O, it contains 2 hydrogen atoms. Using this information, we can calculate the number of moles in 301 grams of water and then determine the number of hydrogen atoms present.
There are 4.8 x 10^24 hydrogen atoms in 360 grams of water. This is calculated by using Avogadro's number to convert the mass of water to moles, and then using the chemical formula of water (H2O) to determine the number of hydrogen atoms present in 1 mole of water.
There are 24 moles of hydrogen in 4 moles of CH4 because each molecule of CH4 contains 4 hydrogen atoms. Therefore, you have 24 moles x 6.022 x 10^23 atoms/mol = 1.4448 x 10^25 atoms of hydrogen.
Balanced equation first. 2H2 + O2 -> 2H2O 250 moles O2 (2 mole H2O/1 mole O2) = 500 mole H2O produced now, since I am forgetful, I will use density formula at 25 C Density = grams/milliliters 500 moles H2O (18.016 grams/1 mole H2O) = 9008 grams H2O 0.9982 g/ml = 9008 grams/milliliters 9024.24 milliliters H2O this is...... 9.02 liters of water produced in this reaction.
If carbon dioxide reacts with hydrogen to form water, the balanced chemical equation is: CO2 + 2H2 -> CH2O + 2H2O. It shows that 1 mole of CO2 produces 2 moles of H2O. Therefore, from 25 moles of CO2, 50 moles of H2O can be produced.
For this you need the atomic (molecular) mass of H2O. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. H2O= 18.0 grams2.5 moles H2O × (18.0 grams) = 45.0 grams H2O
25x(2/18)=2.78g of hydrogen 25x(16/18)=22.22g of oxygen
To determine how many hydrogen atoms are in 301 grams of H2O, we need to consider the molar mass of water (H2O). The molar mass of water is approximately 18 grams/mole. Since the molecular formula of water is H2O, it contains 2 hydrogen atoms. Using this information, we can calculate the number of moles in 301 grams of water and then determine the number of hydrogen atoms present.
There are 24 moles of hydrogen in 4 moles of CH4 because each molecule of CH4 contains 4 hydrogen atoms. Therefore, you have 24 moles x 6.022 x 10^23 atoms/mol = 1.4448 x 10^25 atoms of hydrogen.
There are 4.8 x 10^24 hydrogen atoms in 360 grams of water. This is calculated by using Avogadro's number to convert the mass of water to moles, and then using the chemical formula of water (H2O) to determine the number of hydrogen atoms present in 1 mole of water.
Balanced equation first. 2H2 + O2 -> 2H2O 250 moles O2 (2 mole H2O/1 mole O2) = 500 mole H2O produced now, since I am forgetful, I will use density formula at 25 C Density = grams/milliliters 500 moles H2O (18.016 grams/1 mole H2O) = 9008 grams H2O 0.9982 g/ml = 9008 grams/milliliters 9024.24 milliliters H2O this is...... 9.02 liters of water produced in this reaction.
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2300 grams O2 x 1 mole O2/32 g = 9.375 moles O2Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 molesgrams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)
There are four molecules of water in 4H2O. One molecule of water is written as H2O. The subscript 2 tells you that there are two H(hydrogen) atoms. Since there is no subscript after the O there is one O(oxygen) atom. Now back to 4H2O. The coefficient 4 tells you there are four molecules of H2O. Therefore there are eight H(hydrogen) atoms and four O(oxygen) atoms.
How many hydrogen atoms are in 35.0 grams of hydrogen gas?