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Balanced equation first.

2H2 + O2 -> 2H2O

250 moles O2 (2 mole H2O/1 mole O2)

= 500 mole H2O produced

now, since I am forgetful, I will use density formula at 25 C

Density = grams/milliliters

500 moles H2O (18.016 grams/1 mole H2O)

= 9008 grams H2O

0.9982 g/ml = 9008 grams/milliliters

9024.24 milliliters H2O

this is......

9.02 liters of water produced in this reaction.

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13y ago
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90g water

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Q: How many liters of water can be produced if 250 moles of O2 are reacted with excess hydrogen?
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