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Assuming we are at standard temperature and pressure (STP), the answer is approximately 1.85L of hydrogen gas. The HCl is the limiting reactant and the Mg is the excess reactant.

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Q: How many liters of hydrogen gas are formed from 6.0 g of HCl and 5.0 g of mg?
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How many liters of HCl are produced by the reaction of 5.7 L of hydrogen with an equal amount of chlorine H2 g Cl2 g -- 2 HCl g?

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How would you find the answer to this question How many moles of HCl can be formed when moles of hydrogen gas react with chlorine?

For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl


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There are no atoms of HCl in one molecule of HCl, because HCl is not an atom. It is a molecule. HCl is made of two parts: hydrogen atoms, and chlorine atoms. Each molecule of HCl contains one hydrogen atom and one chlorine atom. H stands for hydrogen, and Cl stands for chlorine. Compare this to H2O, which is the chemical formula for water. Water has 2 hydrogen atoms and 1 oxygen atom.


How many moles of solute are in 50 mL of a 12 M HCl solution?

Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl


How many elements does hcl?

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How many moles of hydrogen gas will be produced from 250.0 milliliters of a 3.0 M HCl in an excess of Mg?

I assume you mean this reaction. Mg + 2HCl -> MgCl2 + H2 need moles HCl as it limits Molarity = Moles of solute/Liters of solution ( 250.0 ml = 0.250 L ) 3. 0 M HCl = moles HCl/0.250 liters = 0.75 moles HCl ----------------------------now, refer to equation and drive reactant against product to get moles H2 0.75 moles HCl (1 mole H2/2 mole HCl) = 0.375, or 0.38 mole hydrogen gas produced ------------------------------------------------------------


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