The answer is 15,039 g hydrogen chloride (HCl).
Moles of solute/ kg of solvent = 2 molal solution
The answer is 15,015 g.
The melting point of water is lowered by 1.85 degrees Celsius if 29.2 grams of salt are dissolved in each Kg of water (called a "0.5 molal solution" of salt). So normal saline, a 0.9 molal solution), is lowered juts less thantwice this or 3.33 deg C. So normal saline freezes at -3.33 deg C or 26 deg F.
1.0 molal
During the determination of the partial molal quantities the weight of the solution to which a substance is added is taken into consideration while in case of the partial molar quantity the volume is taken into consideration.
Don't try this at home, since Li2S can react very violently with water (much like lithium or sodium metal in water).
Moles of solute/ kg of solvent = 2 molal solution
The answer is 15,015 g.
The melting point of water is lowered by 1.85 degrees Celsius if 29.2 grams of salt are dissolved in each Kg of water (called a "0.5 molal solution" of salt). So normal saline, a 0.9 molal solution), is lowered juts less thantwice this or 3.33 deg C. So normal saline freezes at -3.33 deg C or 26 deg F.
How many grams of hydrogen peroxide (H2O2) must be added to 1,500 mL of water to produce a concentration of 1.33 m (molal solution)? (Recall that the density of water is 1.0 gram/mL
yes
Uric acid is an entirely different compound than salt, so I do not see how there is an equivalence between the two.
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
The boiling point is 101 oC.
1.0 molal
Aprox. 830 g.
It is defined aste depression in freezing point of solution containing non-volatile solute.wen molality is equal to 1 and is caled molal depression constant i.e. Tf=kf . m