The answer is 15,015 g.
.25
Moles of solute/ kg of solvent = 2 molal solution
Well the definition of molarity is how many moles in every litre. You already have your answer expressed as moles in a litre, approximately. Density is approximately 1000g per litre, therefore it will be approximately 2 molar. (You haven't expressed temperature, but density should remain close to 1).
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
0.8M means that a 1 litre solution contains 0.8 moles of solute dissolved in it
Moles of solute/ kg of solvent = 2 molal solution
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
Well the definition of molarity is how many moles in every litre. You already have your answer expressed as moles in a litre, approximately. Density is approximately 1000g per litre, therefore it will be approximately 2 molar. (You haven't expressed temperature, but density should remain close to 1).
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
All of the moles of pure acid will have dissolved in the flask.
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
Molality = moles of solute / kilograms of solventm = 5.10 / 4.47m = 1.14 molal
molality = moles solute/kg solvent moles solute = 38.0g x 1 mol/342 g = 0.111 moles kg solvent = 175 g x 1kg/1000g = 0.175 kg molality = 0.111 moles/0.175 kg = 0.635 m
8 moles