HomeHow many moles of urea 60.0 g mol must be dissolved in 100.0g of water to give a 2.5 molal solution?
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Moles of solute/ kg of solvent = 2 molal solution
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
Assuming you mean 2 M solution and not 2 m (molal), you would do it as follows:2.0 moles/L x 1.5 liters = 3.0 moles KNO3 must be dissolved in 1.5 liters.
Well the definition of molarity is how many moles in every litre. You already have your answer expressed as moles in a litre, approximately. Density is approximately 1000g per litre, therefore it will be approximately 2 molar. (You haven't expressed temperature, but density should remain close to 1).
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
The number of moles of solute dissolved in 1 L of a solution would be the molarity. As an example, if you had 2 moles of solute in 1 liter the molarity would be 2M.
moles of NaCl in the solution = mass of dissolved NaCl/58,44
6 moles of solute dissolved in 4 liters of solution.
Molarity = moles of solute / liters of solution moles = Molarity x liters = 0.150 x .250 = 0.0375 moles
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
Molality (m) is moles of solute per kg of solvent. 3 moles/6 kg = 0.5 molal.
All of the moles of pure acid will have dissolved in the flask.
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
moles of a solute in a solution = mass of the dissolved solute/molar mass of the solute
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
Na2SO4 -> 2Na+ +SO42- So, if one mole of Na2SO4 is dissolved in water, two moles of the sodium cation will be found in the solution.
Molarity=moles of solute/liters of solvent=5mol/10L=0.5M
I need this too. I've read that it may be the Van't Hoff factor.
Molal volume is another name for Atomic volume. Molar volume is the number of moles/liter (in SI units).
Theoretically 16 moles but nitrogen monofluoride is unstable and I suppose that this solution cannot be prepared.
You mean solution right, not solutipon? lolIt is called the van't Hoff factor (i)
molality = moles solute/kg solvent moles solute = 38.0g x 1 mol/342 g = 0.111 moles kg solvent = 175 g x 1kg/1000g = 0.175 kg molality = 0.111 moles/0.175 kg = 0.635 m
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ==================
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
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