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What is the molality of a solution composed of 38.0 g of cane sugar (C12H 22O11) dissolved in 175 g of water?

Updated: 4/28/2022

Wiki User

∙ 8y ago

Best Answer

molality = moles solute/kg solvent

moles solute = 38.0g x 1 mol/342 g = 0.111 moles

kg solvent = 175 g x 1kg/1000g = 0.175 kg

molality = 0.111 moles/0.175 kg = 0.635 m

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∙ 8y ago

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