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What is the molality of a solution that contains 5.10 mol KNO3 in 4.47 kg water?
Wiki User
∙ 11y ago
Molality = moles of solute / kilograms of solvent
m = 5.10 / 4.47
m = 1.14 molal
Wiki User
∙ 11y ago
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Will 110 g of KNO3 in 100 g of water at 40 degrees Celsius be saturated or unsaturated?
KNO3 140 g/100 g of water is a saturated solution at about 70 to 75 oC. The solubility change with temperature and it need to be stated for reference temperature. For standard room temperature, KNO3 is saturated at 38.3 g/ 100 g water.
How may grams of KNO3 should be used to prepare a 2.0L of a 0.50 M solution?
Get moles by; Molarity = moles of solute/Liters of solution 0.50 M KNO3 = moles KNO3/2.0 L = 1.0 mole KNO3 Now find grams of 1.0 mole KNO3 1.0 mole KNO3 (101.11 grams/1 mole KNO3) = 101.11 grams KNO3 needed call it 100 grams
Why cannot 100ml of KNO3 solution hold more than 37gm of KNO3 in a dissolved state?
Why 100 ml solution of KOH3 can not hold more than 37gm of KNO3 in dissolved state
Is KNO3 ionic?
When in doubt, look at the reactants that produce the substance. Potassium nitrate, KNO3, is produced in solution by mixing potassium hydroxide, KOH, and nitric acid, HNO3, which are both strong electrolytes, and so is potassium nitrate. Two strong electrolytes will produce a strong electrolyte, a weak and a strong electrolyte will produce a weak electrolyte, and two weak electrolytes will produce a weak electrolyte.
The solubility of kno3 is 155g per 100g of water at 75 degree c and 38g at 25degreec the mass of kno3 will crystallize out of solution if 100g of it saturated solution is cooled from 75c to 25 c is?
I have read two methods to solve this up: the first says that at 75 degrees the solution mass is 100g of water + 155 g of KNO3 so its mass is 255g at 25 degrees the solution mass is 100 g of water + 38 g of KNO3 so its mass is 38 when we cool it down from 75 to 25 we will get 255-138=117g but this is the solution mass and u only want the mass of KNO3 because that is what will really crystallize...so for some reason i really dont get u do 117/255 and then multiply it by the mass of the demanded solution which is 100 g so the answer will be 45.88g nearly 45.9 g the second method is to assume that at 75 degrees there is in 100g of saturated solution, x g of water so KNO3 will be 1.55x total mass 100 x+1.55x=100 x= 39.126 1.55x=60.784 so at 25 degrees there is 0.39 x of KNO3 and x is 39.126 that means there is 0.38*39.126= 14.867 g of KNO3 therefore the mass of KNO3 that will crystallize is 60.784-14.867=45.917= 45.917 why 1.55x? because for each 100 g of water we have 155 g of solute...so 155/100 = the mass of solute for the new water mass/ the new water mass (x) so the mass of solute for the new water mass will be: 155x/100 or 1.55x! the same applies to 0.38x hope this helped =)
How do you separate KNO3 from aqueous sol of KNO3?
It can be separated by boiling off the water or crystallizing the KNO3 from solution
A KNO3 solution containing 45 g of KNO3 per 100g of water is cooled from 40 degrees celciuswhat will happen during cooling?
As the solution is cooled, the solubility of the solution decreases and a precipitate will form.
An aqueous KNO3 solution is made using 89.9g of KNO3 diluted to a total solution volume of 1.35L?
1.0 molal
Will 110 g of KNO3 in 100 g of water at 40 degrees Celsius be saturated or unsaturated?
KNO3 140 g/100 g of water is a saturated solution at about 70 to 75 oC. The solubility change with temperature and it need to be stated for reference temperature. For standard room temperature, KNO3 is saturated at 38.3 g/ 100 g water.
Which solution would elevate the boiling point of water the most MgF2 glucose KNO3 KBr?
MgF2
How may grams of KNO3 should be used to prepare a 2.0L of a 0.50 M solution?
Get moles by; Molarity = moles of solute/Liters of solution 0.50 M KNO3 = moles KNO3/2.0 L = 1.0 mole KNO3 Now find grams of 1.0 mole KNO3 1.0 mole KNO3 (101.11 grams/1 mole KNO3) = 101.11 grams KNO3 needed call it 100 grams
The molar solubility of is not affected by the pH of the solution Na3PO4 NaF KNO3 AlCl3 or MnS?
kno3
What is the molarity of a solution that contains 5.10 mol KNO3 in 4.47 kg?
Without knowing the temperature, we'll assume 1 kilogram = 1 litre of water. Therefore if it is 5.1 mole per litre, it is 5.1 molar.
Why cannot 100ml of KNO3 solution hold more than 37gm of KNO3 in a dissolved state?
Why 100 ml solution of KOH3 can not hold more than 37gm of KNO3 in dissolved state
Why solution becomes hot when you add KNO3?
It doesn't
Is KNO3 ionic?
When in doubt, look at the reactants that produce the substance. Potassium nitrate, KNO3, is produced in solution by mixing potassium hydroxide, KOH, and nitric acid, HNO3, which are both strong electrolytes, and so is potassium nitrate. Two strong electrolytes will produce a strong electrolyte, a weak and a strong electrolyte will produce a weak electrolyte, and two weak electrolytes will produce a weak electrolyte.
The solubility of kno3 is 155g per 100g of water at 75 degree c and 38g at 25degreec the mass of kno3 will crystallize out of solution if 100g of it saturated solution is cooled from 75c to 25 c is?
I have read two methods to solve this up: the first says that at 75 degrees the solution mass is 100g of water + 155 g of KNO3 so its mass is 255g at 25 degrees the solution mass is 100 g of water + 38 g of KNO3 so its mass is 38 when we cool it down from 75 to 25 we will get 255-138=117g but this is the solution mass and u only want the mass of KNO3 because that is what will really crystallize...so for some reason i really dont get u do 117/255 and then multiply it by the mass of the demanded solution which is 100 g so the answer will be 45.88g nearly 45.9 g the second method is to assume that at 75 degrees there is in 100g of saturated solution, x g of water so KNO3 will be 1.55x total mass 100 x+1.55x=100 x= 39.126 1.55x=60.784 so at 25 degrees there is 0.39 x of KNO3 and x is 39.126 that means there is 0.38*39.126= 14.867 g of KNO3 therefore the mass of KNO3 that will crystallize is 60.784-14.867=45.917= 45.917 why 1.55x? because for each 100 g of water we have 155 g of solute...so 155/100 = the mass of solute for the new water mass/ the new water mass (x) so the mass of solute for the new water mass will be: 155x/100 or 1.55x! the same applies to 0.38x hope this helped =)
