8 moles
The molarity is calculated by dividing the moles of solute by the liters of solution. In this case, with 2 moles of compound dissolved in 4 liters of water, the molarity would be 0.5 M (2 moles / 4 L = 0.5 M).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
The molarity is calculated by dividing the moles of solute by the liters of solution. In this case, with 2 moles of compound dissolved in 4 liters of water, the molarity would be 0.5 M (2 moles / 4 L = 0.5 M).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
We need 8 moles potassium chloride.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
The molarity of a solution is the amount of substance in a given amount of solute. The units are usually given as moles per liter (or dm3). As such, for each liter you have 0.5 moles of substance (2 divided by 4), so it's a 0.5 molar solution.
0.2
To make a two mole salt solution in two liters of water, you'll need 4 moles of salt (2 moles/L * 2 L = 4 moles). The molar mass of salt (NaCl) is approximately 58.44 g/mol, so 4 moles would be 233.76 grams (4 moles * 58.44 g/mol = 233.76 g).
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
To find the mass of NaCl present in the solution, we first need to calculate the number of moles of NaCl in the solution using the formula: moles = molarity x volume. The volume here is 150 g of water, which is approximately 150 mL. Therefore, the moles of NaCl in the solution would be (0.050 mol/L) x (0.150 L) = 0.0075 moles. The molar mass of NaCl is 58.44 g/mol, so the mass of NaCl in the solution is 0.0075 moles x 58.44 g/mol = approximately 0.44 g.