For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl.
H2 + Cl2 = 2 HCl
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
The formula of trichloromethane is CHCl3. The usual molar formulas of the three elements are C, H2, and Cl2. Based on these formulas, one mole of trichloromethane contains one mole of carbon, one-half mole of hydrogen, and one and one-half moles of chlorine.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
Lithium can never be formed from hydrogen chloride in a chemical reaction, because lithium, hydrogen, and chlorine are all distinct elements, none of which can be converted any others by chemical means.
When 1 mole of hydrogen reacts with 1 mole of chlorine, 2 moles of hydrogen chloride are formed. The molar mass of hydrogen chloride is 36.46 g/mol. Therefore, 2 moles of hydrogen chloride would have a mass of 72.92 grams.
1 mole of hydrogen reacts with 1 mole of chlorine to form 2 moles of hydrogen chloride. The molar mass of hydrogen chloride is 36.46 g/mol. Therefore, 2 moles of hydrogen chloride would have a mass of 72.92 g.
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
The Atomic Mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
The amount of water formed from a reactionof hydrogen and oxygen conforms to the chemical equation: 2H2 + O2 --> 2H2O For every two moles of hydrogen which reacts with one mole of oxygen, 2 moles of water are formed.
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
The mass of 2,4 moles of chlorine is 84,08 g.
To find the empirical formula, you first need to determine the moles of titanium and chlorine in the compound. The molar mass of titanium is 47.87 g/mol, and chlorine is 35.45 g/mol. From the given masses, you can calculate the moles of titanium and chlorine in the compound. Then, divide the moles by the smallest number of moles to get the mole ratio for the empirical formula. In this case, the empirical formula of the chloride formed is TiCl3.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
To find the number of moles of atoms in 75.10 grams of chlorine, you need to first determine the molar mass of chlorine. Chlorine has a molar mass of approximately 35.45 g/mol. Next, you can use the formula Moles = Mass / Molar Mass to calculate the moles of chlorine atoms in 75.10 grams. This would result in approximately 2.12 moles of chlorine atoms.
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.