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How many grams of hydrogen chloride can be produced from 0.490 g of hydrogen and 50.0 g of chlorine?
The Atomic Mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
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Will 20 grams of hydrogen react with 20 grams of chlorine to form 40 grams of HCL?
No, the reaction between hydrogen and chlorine to form hydrogen chloride does not result in a doubling of mass. The balanced chemical equation for the reaction is: H2 + Cl2 → 2HCl So, according to the equation, 20 grams of hydrogen reacting with 20 grams of chlorine will form 36.5 grams of hydrogen chloride.
How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?
266,86 g aluminium chloride are obtained.
What mass of hydrogen chloride is formed when 1 mole of hydrogen reacts with 1 mole of Chlorine?
When 1 mole of hydrogen reacts with 1 mole of chlorine, 2 moles of hydrogen chloride are formed. The molar mass of hydrogen chloride is 36.46 g/mol. Therefore, 2 moles of hydrogen chloride would have a mass of 72.92 grams.
If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?
75 g sodium chloride contain 29,75 g sodium.
How many moles of hydrogen chloride can be produced from 0.490 grams of Hydrogen and 50.0 grams of chlorine?
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
How many grams of Chlorine are in 7 grams of Sodium Chloride?
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
What volume of Hydrogen chloride gas is produced by 40cm3 of chlorine with hydrogen?
It is necessary first to determine how many moles of chlorine there are in the volume specified. Using the ideal gas law, 40 cm3 of chlorine is equivalent to 0.129 grams of Cl2, or 3.63 millimoles. Next, the stoichiometric equation is set up. X H2 + Y Cl2 -- reacts --> Z HCl. It can be clearly seen that X = 1, Y = 1, and Z = 2. This means that for every mole of chlorine that reacts, 2 moles of hydrogen chloride is produced. Then, we have 7.26 millimoles of HCl. Reversing the ideal gas law, this means the resulting volume of HCl gas is .224 cm3. The reason for the smaller volume is due to the differences in the molar weight of chlorine and hydrogen chloride (70.906 g/mol and 36.461 g/mol respectively).
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
If 4.0 g of hydrogen react with chlorine to produce 146 g of hydrogen chloride how many grams of chlorine reacted?
The balanced chemical equation for the reaction between hydrogen and chlorine is: H2 + Cl2 -> 2HCl. From the equation, we see that 1 molecule of Cl2 reacts with 1 molecule of H2 to produce 2 molecules of HCl. Thus, 4.0 g of hydrogen would react with 118.5 g of chlorine (146 g of hydrogen chloride - 27.5 g of hydrogen).
There is 46 grams of sodium and 23 grams of Chlorine How many gram of sodium chloride can be produced?
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
How many grams of chlorine gas are needed to make 117 grams of sodium chloride?
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
