The answer is 8,33 moles.
The answer is 0,44 moles.
The answer is 97,66 moles.
200. The formula is for every 1 Oxygen atom, 2 Hydrogen atoms must be present in water. Otherwise you would produce H2O2 (you cannot make it HO because it is never found in molecules on it's own) which is bleach.
To determine the moles of H2O required for the reaction with 0.24 moles of Cl2, we first need the balanced chemical equation. For example, in the reaction of chlorine gas with water, Cl2 + H2O → HCl + HOCl, one mole of Cl2 reacts with one mole of H2O. Therefore, 0.24 moles of Cl2 would require 0.24 moles of H2O.
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
There are 4.17 moles of H2O present in 75.0g of H2O.
H2O or water doesn't have any helium in it.
The answer is 0,44 moles.
3.0 moles of H2O have 54 g.
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
The answer is 97,66 moles.
To calculate the number of moles in 8g of H2O, we must first calculate the molar mass of H2O (18.015 g/mol). Then, we can use the formula moles = mass / molar mass to find that there are approximately 0.444 moles of H2O in 8g.
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
200. The formula is for every 1 Oxygen atom, 2 Hydrogen atoms must be present in water. Otherwise you would produce H2O2 (you cannot make it HO because it is never found in molecules on it's own) which is bleach.