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Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.

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9y ago
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6y ago

4NH3 + 5O2 ==> 4NO + 6H2O balanced equation for the reaction4.5 moles NH3/4 = 1.125

3.2 moles O2/5 = 0.64 THIS IS THE LIMITING REACTANT

moles of H2O formed = 3.2 moles O2 x 6 moles H2O/5 moles O2 = 3.84 moles H2O formed

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9y ago

42.5 g of NH3 is equivalent to around 2.5 moles. Since there are 3 moles of H2O produced for every 2 moles of NH3 used, 3.75 moles of H2O are produced. This around 3.79 g of water.

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Q: How many moles of H2O can be formed when 4.5 moles of NH3 react with 3.2 moles of O2 NH3 plus O2 yields NO plus H2O?
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