According to this balanced equation:
Sodium oxide is a compound that will react with water to form an alkali Na2O + H2O = 2NaOH
Rubidium oxide react with water.
Sodium oxide, Na2O, is a base because it'll react in (and with) water forming sodium hydroxide. (This is a very dangerous, exothermic reaction, so don't try this yourself!). This results in a basic solution. Na2O + H2O --> 2 NaOH
Sodium plus water -> sodium oxide
The products of sodium when it is react with water are Sodium Hydroxide solution and hydrogen gas plus heat.
155.2 g
Na + 2H2O -----> H2 + NaOH If you have 2.5 moles water you need 1.25 mol elemental sodium
Sodium oxide is a compound that will react with water to form an alkali Na2O + H2O = 2NaOH
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
3.2 moles of water (H2O)
Rubidium oxide react with water.
Sort of. Sodium oxide reacts with water to form sodium hydroxide, which is soluble.
Sodium oxide, Na2O, is a base because it'll react in (and with) water forming sodium hydroxide. (This is a very dangerous, exothermic reaction, so don't try this yourself!). This results in a basic solution. Na2O + H2O --> 2 NaOH
Sodium plus water -> sodium oxide
Sodium is not dissolved in water; sodium react with water.
The products of sodium when it is react with water are Sodium Hydroxide solution and hydrogen gas plus heat.