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How many SO2 molecules are in 1.75 mol of SO2?
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
How many moles are present in 128 grams of sulphur dioxide?
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
Which is the greatest mass of SO2 that can produced from 15.0 mol Cu2S?
To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.
What is the mass percent of oxygon (O) in SO2?
The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.
How many moles of nickel (Ni) atoms are in 125 g Ni?
To find the number of moles of nickel atoms in 125 g of nickel, divide the given mass by the molar mass of nickel. The molar mass of nickel is approximately 58.69 g/mol. Therefore, 125 g Ni / 58.69 g/mol = ~2.13 moles of Ni atoms.
How many SO2 molecules are in 1.75 mol of SO2?
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
How many moles are present in 128 grams of sulphur dioxide?
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
The number of grams in 2.65 mol of So2 is 2.65?
To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.
What is the mass percent of oxygen in SO2?
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
How many grams are in 0.400 mole of SO2?
To calculate the number of grams in 0.400 moles of SO2, you first need to determine the molar mass of SO2, which is approximately 64.07 g/mol. Then, you multiply the molar mass by the number of moles: 64.07 g/mol x 0.400 mol = 25.63 grams of SO2.
What is the total mass of 0.75 mol of SO2?
The molar mass of sulfur dioxide (SO2) is approximately 64.07 g/mol. Therefore, the total mass of 0.75 mol of SO2 would be 0.75 mol * 64.07 g/mol = 48.05 grams.
Which is the greatest mass of SO2 that can produced from 15.0 mol Cu2S?
To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.
Which of the following reactions shows that the formation of SO2 releases 296.8 kJ mol?
S(s) + O2(g) SO2(g) + 296.8 kJ
What is the percent composition of sulfur in SO2?
32.1g __________________ X100% (32.1g + 16.0g + 16.0g)
What is the mass percent of oxygon (O) in SO2?
The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.
What is the total mass in grams of 0.75 mole of SO2?
To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
