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How many molecules of sulfur dioxide are present in 72 g of the substance?
To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
How many molecules of sulfur dioxide are present in 1.60 moles of sulfur dioxide?
There are approximately 9.65 x 10^23 molecules of sulfur dioxide in 1.60 moles of sulfur dioxide. This is because one mole of any substance contains Avogadro's number of molecules, which is 6.022 x 10^23.
How many moles are in 75 grams of sulfur?
For this you need the atomic mass of He. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.75.0 grams He / (4.00 grams) = 18.8 moles He
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many moles OF s are present 7.71g of s?
To determine the number of moles of sulfur (S) present in 7.71g of S, you should first find the molar mass of sulfur, use it to convert the grams of sulfur to moles. Sulfur has a molar mass of approximately 32.06 g/mol, so the number of moles of S present in 7.71g is 7.71g / 32.06 g/mol = 0.24 moles of S.
How many molecules of sulfur dioxide are present in 72 g of the substance?
To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.
How many atoms are in 37.14 grams of sulfur dioxide?
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
25 moles of sulfur dioxide how many grams of oxygen does it contain?
25 moles of sulfur dioxide contain 600 grams of oxygen. Each mole of SO2 contains 2 moles of oxygen, and the molar mass of O is 16 g/mol. So, 25 moles x 2 moles = 50 moles of O, which is 50 moles x 16 g/mol = 800 g of O.
How many moles of sulfur are in 53.7 grams of sulfur?
To determine the number of moles of sulfur in 53.7 grams, you first need to calculate the molar mass of sulfur, which is approximately 32.06 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.7 grams of sulfur is equivalent to about 1.68 moles.
How many moles are in 6.5 grams of sulfur S?
6,5 grams of sulfur S are equal to 0,203 moles.
How many moles are present in 128 grams of sulphur dioxide?
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
How many grams are in 2.6 moles of sulfur?
2,6 moles of sulfur are equal to 83,356 g.
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
How many molecules of sulfur dioxide are present in 1.60 moles of sulfur dioxide?
There are approximately 9.65 x 10^23 molecules of sulfur dioxide in 1.60 moles of sulfur dioxide. This is because one mole of any substance contains Avogadro's number of molecules, which is 6.022 x 10^23.
How much space will 2.3 grams of sulfur dioxide take up at standard temperature and pressure?
we first find the number of moles( number of moles= mass/molar mass). the we can find the volume by using the formule( volume=number of moles multiplyd by the molar volume)
