48 g
To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
The molar mass of SO2 is approximately 64.07 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles by the molar mass: 0.75 moles x 64.07 g/mol = 48.05 grams Therefore, the total mass of 0.75 moles of SO2 is 48.05 grams.
To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.
The molar mass of SO2 is approximately 64.07 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles by the molar mass: 0.75 moles x 64.07 g/mol = 48.05 grams Therefore, the total mass of 0.75 moles of SO2 is 48.05 grams.
The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.
To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
The molar mass of sulfur dioxide (SO2) is 64.06 g/mol. The molar mass of sulfur is 32.06 g/mol. Calculate the mass percent of sulfur in SO2 using the formula (mass of sulfur / mass of SO2) x 100%. This gives a mass percent of sulfur in SO2 as 50%.
32.1g __________________ X100% (32.1g + 16.0g + 16.0g)
The molecular mass of sulfur dioxide is 64,07.
The relative atomic mass of sulfur is 32.06 g/mol and the relative atomic mass of oxygen is 16.00 g/mol. Therefore, the relative molecular mass of SO2 (sulfur dioxide) is 32.06 + (16.00 x 2) = 64.06 g/mol.