(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
I assume you mean mass of oxygen % in SO2. This is calculated by finding the molecular weight of S and O (32 and 16 respectively) As there are 2 oxygens, 16 is multiplied by 2, = 32. put 32 over the total, = 32/64. Which equals 50%
In sulfur dioxide (SO2), the molar mass of sulfur (S) is 32.07 g/mol, and for oxygen (O) it is 16.00 g/mol. Therefore, the molar mass of SO2 is 32.07 g/mol (S) + 2 * 16.00 g/mol (O) = 64.07 g/mol. If you know the mass of the sample, you can calculate the number of moles of sulfur and oxygen using their respective molar ratios in SO2.
FeO is 50 mole % Fe and 50 mole % O FeO is 77.73 mass % Fe and 22.27 mass % O mass fraction X = molar mass X / (total molar mass of compound) mass % Fe = [atomic mass Fe] / ([atomic mass Fe] + [atomic mass O])
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of carbon, hydrogen, and nitrogen. The total mass of the compound is 136.6 g (C) + 26.4 g (H) + 31.8 g (N) = 194.8 g. The mass of oxygen can be calculated by subtracting the total mass of the compound from the given mass of the sample: 230 g - 194.8 g = 35.2 g. Therefore, the mass percent of oxygen in the compound is (35.2 g / 230 g) x 100% ≈ 15.3%.
First calculate the molar mass of the potassium chlorate KClO3 K is 39.1, Cl is 35.45 and O is 16 x 3 =48 The molar mass for one mol is 122.55g/mol The percent composition is the part the oxygen contributed divided by the total molar mass times 100(to convert a decimal to a percent) 48/122.55 x 100 is 39.167% Potassium Chlorate is 39.167 percent oxygen
I assume you mean mass of oxygen % in SO2. This is calculated by finding the molecular weight of S and O (32 and 16 respectively) As there are 2 oxygens, 16 is multiplied by 2, = 32. put 32 over the total, = 32/64. Which equals 50%
The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.
The percent composition of SO2 is approximately 50% sulfur and 50% oxygen.
To find the percent by mass of oxygen in propanal (CH3CH2CHO), calculate the molar mass of oxygen (O) and the molar mass of the entire compound. Then divide the molar mass of oxygen by the molar mass of the entire compound and multiply by 100 to get the percentage. In this case, the percent by mass of oxygen in propanal is around 47.3%.
In sulfur dioxide (SO2), the molar mass of sulfur (S) is 32.07 g/mol, and for oxygen (O) it is 16.00 g/mol. Therefore, the molar mass of SO2 is 32.07 g/mol (S) + 2 * 16.00 g/mol (O) = 64.07 g/mol. If you know the mass of the sample, you can calculate the number of moles of sulfur and oxygen using their respective molar ratios in SO2.
Sulfur (S) and oxygen (O) are the two elements in sulfur dioxide (SO2).
The percent composition of oxygen in BeO is approximately 89.7%. This can be calculated by dividing the molar mass of oxygen by the molar mass of BeO and multiplying by 100.
The chemical formula for sodium oxide is Na2O. To determine the mass percent of oxygen in Na2O, we need to calculate the molar mass of oxygen (O) and sodium oxide (Na2O), then use these values to calculate the mass percent of oxygen in Na2O.
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
Oxygen is 49.95% of the mass of SO2. The molecular weight is 48.06 g/mol and sulfur's molecular weight is 32.06 g/mol, so oxgyen must make up the other half of the compounds molecular weight.
FeO is 50 mole % Fe and 50 mole % O FeO is 77.73 mass % Fe and 22.27 mass % O mass fraction X = molar mass X / (total molar mass of compound) mass % Fe = [atomic mass Fe] / ([atomic mass Fe] + [atomic mass O])