I assume you mean mass of oxygen % in SO2.
This is calculated by finding the molecular weight of S and O (32 and 16 respectively)
As there are 2 oxygens, 16 is multiplied by 2, = 32.
put 32 over the total, = 32/64. Which equals 50%
The mass percent of oxygen in SO2 is 50 %.
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
The percent by mass of oxygen in N2O4 is 69,56 %.
60%
The mass of the elements that are not oxygen equals 194.8g. The mass of oxygen is 230g - 194.8g = 35.2g of oxygen. Mass percent of oxygen = 35.2g O/230g x 100 = 15% O
The mass percent of oxygen in SO2 is 50 %.
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
Being friends
The percent by mass of oxygen in N2O4 is 69,56 %.
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
the answer is 29 percent
Estriol (C18H24O3) contain 16,644 % oxygen.
60%
The mass of the elements that are not oxygen equals 194.8g. The mass of oxygen is 230g - 194.8g = 35.2g of oxygen. Mass percent of oxygen = 35.2g O/230g x 100 = 15% O
Oxygen atoms weigh more than Hydrogen atoms.
19.37 g/mol
42.3