The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
The molar mass of MgO is 40.3 g/mol (Mg: 24.3 g/mol, O: 16 g/mol). The molar mass contribution of oxygen in MgO is 16 g/mol. Therefore, the percent composition of oxygen in MgO is (16 g/mol / 40.3 g/mol) * 100 = 39.7%.
The empirical formula of this compound would be MgO.
To calculate the percent error of oxygen in magnesium oxide (MgO), you would compare the experimental value of oxygen in MgO to the theoretical value. The experimental value can be determined by chemical analysis, while the theoretical value can be calculated using the molecular formula of MgO. The percent error is calculated using the formula: (|Theoretical value - Experimental value| / Theoretical value) x 100%.
The mass percent of oxygen is approximately 21% in Earth's atmosphere.
2 Mg(OH)2 have 10 atoms.
The molar mass of MgO is 40.3 g/mol (Mg: 24.3 g/mol, O: 16 g/mol). The molar mass contribution of oxygen in MgO is 16 g/mol. Therefore, the percent composition of oxygen in MgO is (16 g/mol / 40.3 g/mol) * 100 = 39.7%.
The percent composition of magnesium (Mg) in MgO is 60%. This is because there is one magnesium atom (24.3 g/mol) and one oxygen atom (16.0 g/mol) in the formula unit MgO (40.3 g/mol), so dividing the molar mass of magnesium by the molar mass of MgO gives 0.603, or 60.3%.
60%
The empirical formula of this compound would be MgO.
To calculate the percent error of oxygen in magnesium oxide (MgO), you would compare the experimental value of oxygen in MgO to the theoretical value. The experimental value can be determined by chemical analysis, while the theoretical value can be calculated using the molecular formula of MgO. The percent error is calculated using the formula: (|Theoretical value - Experimental value| / Theoretical value) x 100%.
The mass percent of oxygen is approximately 21% in Earth's atmosphere.
2 Mg(OH)2 have 10 atoms.
The percent by mass of oxygen in N2O4 is 69,56 %.
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of magnesium and oxygen: 14.5 g + 3.5 g = 18.0 g. Then, use the formula for mass percent: (mass of oxygen / total mass) × 100%. Thus, the mass percent of oxygen is (3.5 g / 18.0 g) × 100% ≈ 19.44%.
To find the percent by mass of oxygen in propanal (CH3CH2CHO), calculate the molar mass of oxygen (O) and the molar mass of the entire compound. Then divide the molar mass of oxygen by the molar mass of the entire compound and multiply by 100 to get the percentage. In this case, the percent by mass of oxygen in propanal is around 47.3%.
Magnesium nitride (Mg3N2) has a higher percentage composition of magnesium than magnesium oxide (MgO) does. The percentage composition of magnesium in magnesium nitride is 72.2% and the percentage composition of magnesium in magnesium oxide is 60.3%.
To find the percent of oxygen by mass in a compound, you need to know the molar mass of the compound and the molar mass of oxygen. Divide the molar mass of oxygen by the molar mass of the compound and multiply by 100 to get the percentage.