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Who has more atoms 50g of magnesium or 50g of lithium?
50g of magnesium has more atoms because magnesium has a higher atomic mass compared to lithium.
What is the percent composition of magnesium Mg in MgO?
The percent composition of magnesium (Mg) in MgO is 60%. This is because there is one magnesium atom (24.3 g/mol) and one oxygen atom (16.0 g/mol) in the formula unit MgO (40.3 g/mol), so dividing the molar mass of magnesium by the molar mass of MgO gives 0.603, or 60.3%.
Why Magnesium metal is a better conductor than Sodium metal?
Magnesium metal is a better conductor than Sodium metal because it has more free electrons to carry electric charge due to its atomic structure. Magnesium has two electrons in its outer shell, compared to Sodium's one, making it a more efficient conductor of electricity. Additionally, the higher atomic mass of Magnesium allows for better mobility of electrons, resulting in higher conductivity.
What is the mass number for Mg?
Magnesium is a metal element. Mass number of it is 24.
How many mg of Magnesium will reqiured to prepare 60ml of 20 percent solution?
To calculate the mass of magnesium needed, use the formula: mass of solute = volume of solution (ml) x percentage concentration / 100. In this case, it would be 60 ml x 20% = 12 g or 12,000 mg of magnesium will be required to prepare 60 ml of a 20% solution.
When magnesium burns in pure nitrogen gas magnesium nitride is formes what mass of magnesium must be provided in order to produce 1.19 grams of magnesium nitride?
To calculate the mass of magnesium needed to produce 1.19 grams of magnesium nitride, you need to consider the stoichiometry of the reaction. The molar mass of Mg3N2 (magnesium nitride) is 100.93 g/mol. From the balanced equation, 6 moles of magnesium is needed to produce 1 mole of magnesium nitride. Therefore, you can use the molar mass of magnesium and molar ratio to determine the mass needed.
What is the chemical name for Mg3N3?
The chemical name for Mg3N2 is magnesium nitride.Mg = MagnesiumN = NitrogenIts molar mass is 100.9494 g/mol.
How many grams of magnesium nitride can be made from 55.3 grams of magnesium if all the magnesium reacts only with nitrogen?
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
What is the molar mass of magnesium nitride (Mg3N2) if the molar mass of magnesium is 24.31g and nitrogen is 14.01g?
Need formula of magnesium nitride, an ionic compound. Mg2+ and N3- together make Mg3N2 -------------- so 3 * 24.31 g = 72.93 grams 2 * 14.01 g = 28.02 grams ------------------------------------------add = 100 .95 grams/mole --------------------------------molar mass magnesium nitride
HOW TO GET percent of magnesium by mass?
To calculate the percentage of magnesium by mass in a compound, divide the mass of magnesium by the total mass of the compound, then multiply by 100. Percentage of magnesium by mass = (mass of magnesium / total mass of compound) * 100.
What is the percent compostition of magnesium chlorate?
Magnesium chlorate has a percent composition of approximately 16.4% magnesium, 21.8% chlorine, and 61.8% oxygen by mass.
When magnesium is burned in air is the product formed heavier lighter or the same mass as the magnesium that you started with?
Both products MgO (magnesium oxide) and some Mg3N2 (magnesium nitride)are both much heavier than the originating Mg strip before it was set to fire.Mg = 12 g/molMgO = (12+16) = 28 g/mol(1/3)Mg3N2 = (1/3)*(3*12 + 2*14) = 0.33*64 = 21 g/mol
What is the mass percent A compound contains 14.5 g of magnesium and 3.5 g of oxygen. What is the mass percent of oxygen in the compound?
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of magnesium and oxygen: 14.5 g + 3.5 g = 18.0 g. Then, use the formula for mass percent: (mass of oxygen / total mass) × 100%. Thus, the mass percent of oxygen is (3.5 g / 18.0 g) × 100% ≈ 19.44%.
If the surface of the Mg ribbon you used were covered with thin oxide coating prior to the reaction would your mass percent calculation of magnesium be too high or too low explain?
The mass percent calculation of magnesium would be too low if the Mg ribbon's surface were covered with a thin oxide coating prior to the reaction. This is because the oxide coating adds extra mass to the ribbon without contributing to the actual amount of magnesium in the sample being measured.
What is the percent composition of magnesium (mg) on MgO?
60%
What is the percent composition of magnesium in MgCrO4?
To find the percent composition of magnesium in magnesium chromate (MgCrO4), first calculate the molar mass of the compound. The molar mass of magnesium (Mg) is approximately 24.31 g/mol, chromium (Cr) is about 51.996 g/mol, and oxygen (O) is about 16.00 g/mol. Thus, the molar mass of MgCrO4 is 24.31 + (2 × 51.996) + (4 × 16.00) = 200.31 g/mol. The percent composition of magnesium is calculated as (24.31 g/mol ÷ 200.31 g/mol) × 100%, which is approximately 12.13%.
What is the percent composition of magnesium (mg) in mg0?
To find the percent composition of magnesium (Mg) in magnesium oxide (MgO), first determine the molar masses: magnesium has a molar mass of approximately 24.31 g/mol, and oxygen has a molar mass of about 16.00 g/mol. The molar mass of MgO is roughly 40.31 g/mol (24.31 g/mol + 16.00 g/mol). The percent composition of magnesium is then calculated as (24.31 g/mol / 40.31 g/mol) × 100%, which equals approximately 60.3%.
