60%
mg
the ions are 67 and one half since the molecular structuere
This is a chemical change. The reaction is: Mg + O ---> MgO
mg br3
12 mg
I found this at WikiPedia. It's pretty close. Magnesium Hydroxide is Milk of Magnesia. They show Magnesium Hydroxide from a magnesium salt: ----- The chemical formula of sodium hydroxide is NaOH. The chemical formula of magnesium hydroxide is Mg(OH)2.
60%
mg
The percent of Mg calculated will be too high. Let's say that you reacted 1.00 g of Mg and made some MgO, but so much MgO escaped as smoke that only 1.00 g of MgO was left. You would then conclude from the numbers that the mass of O in the MgO was zero! This would lead you to conclude that the percent of Mg in the MgO was 100 %, which is silly and clearly in error. Although this is an extreme example, it illustrates that the loss of MgO as smoke from the crucible leads to a percent of Mg (calculated) that is above the expected 60.3 %.
the symbol of magnesium is Mg.
Mg+O2----->MgO
"MgO" is magnesium oxide and "H" is hydrogen, as in "Mg + H(2)O => MgO + H(2)" MgO + H2 ---> H2O + Mg
the final formula of magnesium oxide is MgO.
Mg + O ----> MgO
The chemical formula of magnesium oxide is MgO.
Half equations ?? The chemical formula of magnesium oxide is MgO.
I'm not entirely sure but an unbalanced equation is: Mg + O2 -----> MgO
2 Mg (s) + O2 (g) → 2 MgO (s)4.00mg x 1 mol Mg/24.305 x 2 mol MgO/2 mol Mg x 40.305g MgO/1 mol MgO==6.63g4.00g- Given24.305g- Atomic Mass of Magnesium40.305g- Atomic Mass of Magnesium Oxide