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The relative Atomic Mass of sulfur is 32.06 g/mol and the relative atomic mass of oxygen is 16.00 g/mol. Therefore, the relative molecular mass of SO2 (sulfur dioxide) is 32.06 + (16.00 x 2) = 64.06 g/mol.
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How many moles in 37.4g of SO2?
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
What is the mass percent of oxygen on SO2?
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
What is the mass of 0.75 mole of so2?
The molar mass of SO2 (sulfur dioxide) is approximately 64.06 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles (0.75) by the molar mass (64.06 g/mol) to get the mass of 0.75 moles of SO2, which is 48.045 grams.
What is molecular weight of so2?
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.
How many moles are in 3.82 g of SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
What is the mass percent of oxygen (O) in SO2?
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
What is the mass percent of oxygen in SO2?
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
How many moles in 37.4g of SO2?
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
What is the mass percent of oxygen on SO2?
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
What is the total mass in grams of 0.75 mole of SO2?
To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.
What is the percent by mass of sulfur in sulfur dioxide?
The molar mass of sulfur dioxide (SO2) is 64.06 g/mol. The molar mass of sulfur is 32.06 g/mol. Calculate the mass percent of sulfur in SO2 using the formula (mass of sulfur / mass of SO2) x 100%. This gives a mass percent of sulfur in SO2 as 50%.
What is the mass percent in oxygen SO2?
I assume you mean mass of oxygen % in SO2. This is calculated by finding the molecular weight of S and O (32 and 16 respectively) As there are 2 oxygens, 16 is multiplied by 2, = 32. put 32 over the total, = 32/64. Which equals 50%
What is the mass of 0.75 mole of so2?
The molar mass of SO2 (sulfur dioxide) is approximately 64.06 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles (0.75) by the molar mass (64.06 g/mol) to get the mass of 0.75 moles of SO2, which is 48.045 grams.
What is molecular weight of so2?
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.
What is the molar mass of so2?
The molecular mass of sulfur dioxide is 64,07.
How many moles are in 3.82 g of SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
