1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
To calculate the number of molecules of SO2 present per cubic meter, you can use Avogadro's number (6.022 x 10^23 molecules/mol). First, convert 3.10 x 10^-6 mol to molecules by multiplying by Avogadro's number to get 1.86 x 10^18 molecules of SO2 per cubic meter.
To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
There are 6.022 x 10^22 molecules in one mole of any substance. Therefore, in a 0.10 mole sample of SO2, there would be 0.10 x 6.022 x 10^22 = 6.022 x 10^21 molecules of SO2.
The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.
To calculate the number of molecules of SO2 present per cubic meter, you can use Avogadro's number (6.022 x 10^23 molecules/mol). First, convert 3.10 x 10^-6 mol to molecules by multiplying by Avogadro's number to get 1.86 x 10^18 molecules of SO2 per cubic meter.
To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.
To calculate the number of grams in 0.400 moles of SO2, you first need to determine the molar mass of SO2, which is approximately 64.07 g/mol. Then, you multiply the molar mass by the number of moles: 64.07 g/mol x 0.400 mol = 25.63 grams of SO2.
The molar mass of sulfur dioxide (SO2) is approximately 64.07 g/mol. Therefore, the total mass of 0.75 mol of SO2 would be 0.75 mol * 64.07 g/mol = 48.05 grams.
To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
S(s) + O2(g) SO2(g) + 296.8 kJ
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
There are 6.022 x 10^22 molecules in one mole of any substance. Therefore, in a 0.10 mole sample of SO2, there would be 0.10 x 6.022 x 10^22 = 6.022 x 10^21 molecules of SO2.
32.1g __________________ X100% (32.1g + 16.0g + 16.0g)
The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.
M means molarity, with units moles/Liter. Using this information, we use dimensional analysis: 2.5mL x (1L/1000mL) x (9mol/1L) = 0.0225mol