M means molarity, with units moles/Liter. Using this information, we use dimensional analysis: 2.5mL x (1L/1000mL) x (9mol/1L) = 0.0225mol
Four moles of sulfur dioxide would consist of how many molecules?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
Four moles of sulfur dioxide would consist of how many molecules?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490 mole SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
Since oxygen is diatomic it requires 2 moles of oxygen.
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.