5.418E23 molecules
There are 6.022x10^23 molecules in 1.00 mol of anything.
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
There are 1.08 x 10^24 sulfur dioxide molecules in 1.80 mol of sulfur dioxide.
The number of bromine molecules present in the flask can be calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol. In this case, there are 0.380 mol of bromine, so the number of bromine molecules present is 0.380 mol x 6.022 x 10^23 molecules/mol.
9.982 is the answer because you take the given mole and multiply it by the mass of N. So it would be 0.713 mol x 14.00 = 9.982 g
The number of molecules is 7,2265690284.10e23.
The answer is 12,046.1023 molecules.
To determine the number of molecules in 45.8 mg of C2H4, we first calculate the number of moles using the molar mass of C2H4 (28.05 g/mol). Then we use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules, which is approximately 1.23 x 10^20 molecules.
The number of molecules is 7,52767607125.10e23.
There are 6.022x10^23 molecules in 1.00 mol of anything.
There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are approximately 5.8 x 10^24 molecules in 9.6 mol of C2H4. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
107,43.10e+23 atoms
To determine the number of molecules in a sample, you need to know the molar mass of the substance. The molar mass of dimethylmercury (CH3)2Hg is approximately 230.65 g/mol. Utilizing the formula: moles = mass/molar mass, and then using Avogadro's number (6.022 x 10^23 molecules/mol), you can calculate the number of molecules in the sample.
To determine the number of molecules in a 4.30 g sample of dimethylmercury (MM = 230.64 g/mol), you need to first calculate the number of moles using the formula: moles = mass / molar mass. Then, you can convert moles to molecules using Avogadro's number (6.022 x 10^23 molecules/mol). So, for dimethylmercury: moles = 4.30 g / 230.64 g/mol, then molecules = moles x 6.022 x 10^23.
To find the number of N2O4 molecules, we first need to calculate the number of moles of N2O4 in 76.3g using the molar mass. We divide 76.3g by 92.02 gmol to find 0.83 mol. Next, we use Avogadro's number, 6.022 x 10^23 molecules/mol, to convert moles to molecules. Multiplying 0.83 mol by Avogadro's number gives us approximately 5 x 10^23 molecules of N2O4 in 76.3g.